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Y_Kistochka [10]
4 years ago
13

B) 75: 125 help me solve it

Mathematics
1 answer:
mash [69]4 years ago
4 0

75:125

divide both sides by 25

75/25= 3

125/25= 5

Answer: 3:5

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A line segment or ray that is perpendicular to the segment at its midpoint is called
Dimas [21]
Perpendicular bisector
3 0
3 years ago
The ratio of the heights of triangles is 2:3. find out the ratio of their areas.
Vitek1552 [10]
The answer to the question is 2:3
4 0
3 years ago
***PLEASE HELP***
Molodets [167]
Given:
250 sheep in a 40-acre pasture.
Number of sheep grazing in each acre.

250/40 = 6.25 or 6 sheep per acre

n = 6
sample proportion: signified by ρ
Sample 1: 4 → 4/6 = 0.67
Sample 2: 1 → 1/6 = 0.17
Sample 3: 9 → 9/6 = 1.50

multiply the sample proportion by 1-ρ
Sample 1: 0.67(1-0.67) = 0.67(0.33) = 0.2211
Sample 2: 0.17(1-0.17) = 0.17(0.83) = 0.1411
Sample 3: 1.50(1-1.5) = 1.5(-0.5) = -0.75

divide the result by n. n = 6
Sample 1: 0.2211/6 = 0.03685
Sample 2: 0.1411/6 = 0.02352
Sample 3: -0.75/6 = -0.125

square root of the quotient to get the standard error.
Sample 1: √0.03685 = 0.1919
Sample 2: √0.02352 = 0.1534
Sample 3: √-0.125 = invalid

z value 95% confidence 1.96.

Sample 1: 1.96 * 0.1919 = 0.3761 or 37.61% margin of error
Sample 2: 1.96 * 0.1534 = 0.3007 or 30.07% margin of error


8 0
4 years ago
Solve x and y 3x-4y=18,9x-2y=12
Rudiy27

Answer:

3x-4y=18

1xy=18

xy=18 ans

4 0
3 years ago
Read 2 more answers
In a polynomials equation do you add the exponents if they are different
Alexus [3.1K]
You can only add exponents if you are multiplying two of the same variable together. For example,
x^{12} \times x^4 = x^{16}

You take them away if you are dividing.
<span>x^{12} \div x^4 = x^{8}

In a polynomial equation, you can add together two of the same variable if they have the same exponent
</span>3x^4 + 7x^4 = 10x^4

Or you can take them away in a similar fashion,
<span>3x^4 - 7x^4 = -4x^4

But you cannot add two (or more) different exponents,
</span>6+4x+7x^2 = 6+4x+7x^2 (it does not get any simpler)

I hope this has answered your question, if not, leave a comment and I'll update the answer.
4 0
3 years ago
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