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3 years ago

Find the area of the shape shown below

Mathematics

1 answer:

sveticcg [70]3 years ago

4 0

Answer:

Step-by-step explanation:

3x3= 9x7= 63

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Karl drove 617.3 miles. For each gallon of gas, the car can travel 41 miles. Select a reasonable estimate of the number of gallo

Hatshy [7]

Answer:

The number of gallons of gas Karl used is 15 gallons.

Option (C) is correct.

Step-by-step explanation:

As given

Karl drove 617.3 miles.

For each gallon of gas, the car can travel 41 miles.

i.e

1 gallons = 41 miles

$1\ miles = \frac{1}{41}\ gallons$

Now find out for the 617.3 miles.

Thus

$617.3\ miles = \frac{617.3}{41}\ gallons$

$617.3\ miles = 15.1\ gallons$

$617.3\ miles = 15\ gallons\ (Approx)$

Therefore the number of gallons of gas Karl used is 15 gallons.

Option (C) is correct.

4 0

3 years ago

Which expression is equivalent to 4+2(1+3x)

Leviafan [203]

Answer:

I'm glad you asked!

Step-by-step explanation:

OK,let's simplify the number for a equivalent expression.

$4+2(1+3x)$

Distribute:

$=4+(2)(1)+(2)(3x)$

$= 4+2+6x$

Combine Like Terms:

$=4+2+6x$

$=(6x)+(4+2)$

$=6x+6$

The Final Answer is : $6x+6$

8 0

3 years ago

Speed cell wireless offers a plan of $40 for the first 400 minutes, and an additional $0.50 for every minute over 400. Let t rep

Jlenok [28]

Answer:

Step-by-step explanation:

c(t)=40:0≤t≤400

=40+0.50 (t-400):t≥400

6 0

3 years ago

Camden is going to invest $600 and leave it in an account for 12 years. Assuming the

UkoKoshka [18]

$~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$920\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &12 \end{cases}$

$920=600e^{\frac{r}{100}\cdot 12}\implies \cfrac{920}{600}=e^{\frac{3r}{25}}\implies \cfrac{23}{15}=e^{\frac{3r}{25}}\implies \log_e\left( \cfrac{23}{15} \right)=\log_e\left( e^{\frac{3r}{25}} \right) \\\\\\ \ln\left( \cfrac{23}{15} \right)=\cfrac{3r}{25}\implies 25\cdot \ln\left( \cfrac{23}{15} \right)=3r\implies \cfrac{25\cdot \ln\left( \frac{23}{15} \right)}{3}=r \\\\\\ 3.5620\approx r\implies \stackrel{\%}{3.56}\approx r$

7 0

2 years ago

write the condition to be satisfied by q so that a rational number p/q has a terminating decimal expansion

hjlf

For a rational number to have a terminating decimal expansion
q should be in the form 5^m and 2^n or both. If q is not in the form of either then it is a non terminating recurring decimal expansion

6 0

3 years ago