Answer:
3600 gallons of water was removed from the basement.
Step-by-step explanation:
Given:
Rate of each pump = 40 gallons/min
We need to find find the number of gallons of water removed from the basement.
Solution:
Now Given:
After half an hour, the one pump burns out.
Now we know that;
1 hour = 60 mins
hour = 
Now for 30 mins both the pumps were working and removing the water.
So we can say that;
Water remove for first 30 mins = 
Also Given:
the second pump finishes removing the water half an hour later.
So we can say that;
Water removed for next 30 mins = 
Now we can say that;
Total water removed from the basement is equal to sum of Water remove for first 30 mins and Water removed for next 30 mins .
framing in equation form we get;
Total water removed from the basement = 
Hence 3600 gallons of water was removed from the basement.
Answer:
V≈146.57ft^3
Step-by-step explanation:
V=πr^2·h/3 since d is 14.4, we would divide it by 2 to find the radius which is 7.2
so V= π(7.2)^2· (2.7)/3
V≈146.57ft^3
It would be greatly appreciated if you gave me the brainlest
For this, all you need to do is subtract 2m on both sides, and your answer will be: -1 = m
(Answer included in imagine)
-12,3 ...................................