All categories

3 years ago

7/10 -___+ 3/2= 6/5Fill in the blanks to make the statement true

Mathematics

1 answer:

VladimirAG [237]3 years ago

6 0

Answer:

Step-by-step explanation:

7/10-x+3/2=6/5

7/10-x=6/5-3/2

7/10-x=-3/10

-x=-10/10

x=1

You might be interested in

Find the solution set for this equation: -a2+4a=0 (Separate the two values with a comma)

Rashid [163]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: \{ 0,4 \}$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: - {a}^{2} + 4a = 0$

$\qquad \tt \rightarrow \: - ( {a}^{2} - 4a) = 0$

$\qquad \tt \rightarrow \: {a}^{2} - 4a = 0$

$\qquad \tt \rightarrow \:a(a - 4) = 0$

The two cases are :

a = 0

a -4 = 0, that leads to a = 4

We can conclude :

$\qquad \tt \rightarrow \:solution \: (a) = \{ 0,4\}$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

5 0

2 years ago

Read 2 more answers

In a particular class, exams are worth 50% of the overall grade, quizzes are worth 30% of the overall grade, homework is worth 1

Paha777 [63]

Answer:

The student's overall grade is 85.79%

Step-by-step explanation:

Given in the question that:

Exam = 50%; Quiz = 30%, Home work = 15% and Class participation = 5%

The total giving us 100%.

A particular student scored the following;

87.9% on exams, 77.8% quiz, 90% Home work and 100% on class participation

Calculating the percentages the student had for each;

Exam total = 50*0.879 = 43.95% earned

Quiz = 30*0.778 = 23.34% earned

Home work = 15*0.9 = 13.5% earned

Class participation = 5*1 = 5% earned

Total earned = 43.95+ 23.34 + 13.5+ 5 = 85.79%

3 0

3 years ago

What is the missing length.

nasty-shy [4]

Answer:

$KS = 12$

Step-by-step explanation:

Given that ∆KLM ~ ∆RSK, $\frac{KL}{KR} = \frac{KM}{KS}$ (similarity theorem)

KL = 65

KR = 65 - 52 = 13

KM = 60

KS = ?

$\frac{65}{13} = \frac{60}{KS}$

Cross multiply

$65*KS = 60*13$

$65*KS = 780$

$\frac{65*KS}{65} = \frac{780}{65}$

$KS = 12$

4 0

3 years ago

What is the exact length of AB? 4 m 8 mm m 2 TT m

dalvyx [7]

Answer:

The answer is

$\pi$

if I am not wrong

Step-by-step explanation:

First you need to convert 45 degress to radians,then you use the arc length formula which is = thr radius * the angle to get the answer

5 0

3 years ago

Plz hurry!!!! thank you!!!!

Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = $\frac{115}{2}$ = 57.5°

Now, tan(57.5°) = $\frac{OS}{SN}$

⇒ 1.5697 = $\frac{R}{SN}$

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = $\frac{NQ}{QM}$

⇒ tan65° = $\frac{NQ}{QM}$

⇒ QM = $\frac{2R}{2.1445}$

QM = 0.9326 R .

⇒ MT = MQ + QT

= 0.9326 R + 0.637 R (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = ( $\frac{NP + MK}{2}$ ) × (ST)

= ( $\frac{1.274 R + 3.1392 R}{2}$ ) × 2 R

= 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0

3 years ago