The general form of a linear equation is y = mx + b where m = slope and b = y-intercept Here m = 2/7 To get to its perpendicular equation, first the slope should be negative reciprocal. So the perpendicular slope is m = -7/2 Given the point (-2,3), use the point-slope form equation, that is y - y1 = m(x - x1) Plug in y - 3 = (-7/2)[x - (-2)] y - 3 = (-7/2)x - 7 y = (-7/2)x - 7 + 3 y = (-7/2)x - 4 That is the equation required.
