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2 years ago

BEEN ASKING FOR A WHILE!! Find the perimeter and area for the triangle. Be sure to write the formula, and use correct measure.

Mathematics

1 answer:

Sauron [17]2 years ago

6 0

Answer:

Area = 77ft²

Perimeter = 44 9/20 feets

Step-by-step explanation:

Area of a triangle = 1/2 * base * height

Base = 19 1/4 feets = 77/4 feets

Height = 8 feets

Area = 1/2 * 77/4 * 8

Area = (77 * 8) / 8

Area = 77 feet²

Perimeter of a triangle :

Sum of the sides

Perimeter = a + b + c

Perimeter = 19 1/4 + 10 + 15 1/5

Perimeter = 44 + (1/4 + 1/5)

Perimeter = 44 9/20

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Find the missing side. Round to the nearest HUNDRETH.

swat32

Answer:

A. 5.34

Step-by-step explanation:

Reference angle = 24°

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Thus, applying trigonometric ratio, we have:

tan (24) = x/12

Multiply both besides by 12

12*tan (24) = x

x = 5.34 (nearest hundredth)

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2 years ago

Is the expression 9 divided by 4 the same as 1/9 x 1/4

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3 years ago

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2 years ago

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Where is the graph?

Step-by-step explanation:

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2 years ago

For the following amount at the given interest rate compounded continuously, find (a) the future value after 9 years, (b) the

Stella [2.4K]

Answer:

(a) The future value after 9 years is $7142.49.

(b) The effective rate is $r_E=4.759 \:{\%}$ .

(c) The time to reach $13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of $P$ dollars is invested at a rate of interest $r$ compounded continuously for $t$ years, the compound amount is

$A=Pe^{rt}$

(a) From the information given

$P=4700$

$r=4.65\%=\frac{4.65}{100} =0.0465$

$t=9 \:years$

Applying the above formula we get that

$A=4700e^{0.0465\cdot 9}\\A=7142.49$

The future value after 9 years is $7142.49.

(b) The effective rate is given by

$r_E=e^r-1$

Therefore,

$r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}$

(c) To find the time to reach $13,000, we must solve the equation

$13000=4700e^{0.0465\cdot t}$

$4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88$

3 0

2 years ago

BEEN ASKING FOR A WHILE!! Find the perimeter and area for the triangle. Be sure to write the formula, and use correct measure. ​

BEEN ASKING FOR A WHILE!! Find the perimeter and area for the triangle. Be sure to write the formula, and use correct measure.