If this is a parabolic motion equation, then it is a negative parabola, which looks like a hill (instead of a positive parabola that opens like a cup). Your equation would be h(t)= -16t^2 + 20t +3. That's the equation for an initial velocity of 20 ft/s thrown from an initial height of 3 ft. And the -16t^2 is the antiderivative of the gravitational pull. Anyway, if you're looking for the maximum height and you don't know calculus, then you have to complete the square to get this into vertex form. The vertex will be the highest point on the graph, which is consequently also the max height of the ball. When you do this, you get a vertex of (5/8, 9.25). The 9.25 is the max height of the ball.
Lets solve the question,
Given dimensions are:
Length = 26 feet
Width = 14 feet
concrete walkway with width = c
After installing the concrete walkway dimensions of the walkway will be,
Length = 26 + 2c
Width = 14 + 2c
She wants to build a wooden deck around the pool with a concrete walkway of width = w
Thus the dimensions of the wooden deck around the pool will be,
Length = 
Width = 
Now the perimeter of the wooden deck will be,
Perimeter = 2(length + width)
![= 2[(26 +2c + 2w) + 2(14 + 2c + 2w)] = 2(40 + 4c + 4w) = (80 + 8c + 8w)](https://tex.z-dn.net/?f=%3D%202%5B%2826%20%2B2c%20%2B%202w%29%20%2B%202%2814%20%2B%202c%20%2B%202w%29%5D%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%202%2840%20%2B%204c%20%2B%204w%29%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%2880%20%2B%208c%20%2B%208w%29)
Therefore, perimeter of the wooden deck would be: 80 + 8c + 8w
Perimeter = (80 + 8c + 8w)
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Answer:
4 x 6 divided by 1/4 and 6
Step-by-step explanation:
i'm sorry if i got it wrong. :(
It is in the thousands place.