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3 years ago

Please help me!!!!!!!!!!!!

Mathematics

2 answers:

Alla [95]3 years ago

4 0

The value of x is 3 hope you did well

earnstyle [38]3 years ago

3 0

The value of x is 3. Hope this helps

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Integers because it uses degrees

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3 years ago

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What is 1 ft^3 to m^3

cluponka [151]

Answer:

1 ft3= 0,028 m3

Step-by-step explanation:

We know that a 1 ft= 0,305 m,

if we cubed the above equation we have the following

1 ft3= (0,305)^3 m3

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2 years ago

A deli owner sold 90 sandwiches in one day. Of those sandwiches, 36 were pastrami.

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Answer: 40%

Step-by-step explanation:

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3 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

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1 year ago

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lilavasa [31]

Answer:

Step-by-step explanation:

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2 years ago