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worty [1.4K]
3 years ago
14

HELP NEEDED 20 POINTS AND BRAINLIST!!!! Please explain your answer and no links! please!

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

From (0,0) and go down 1 and put a dot then down 4 and over to the right 1 and draw a line.

Step-by-step explanation:

Hope this helps have a nice day!

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$x=\log_{10}y

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If m(x) = x2 + 3 and n(x) = 5x + 9, which expression is equivalent to (mn)(x)?
Ilia_Sergeevich [38]
For this case we have the following functions:
 m (x) = x ^ 2 + 3&#10;&#10;n (x) = 5x + 9
 Multiplying both functions, we obtain an expression equivalent to (mn) (x).
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 (mn) (x) = m (x) n (x)&#10;
 Substituting values we have:
 (mn) (x) = (x ^ 2 + 3) (5x + 9)&#10;
 Rewriting the expression we have:
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An expression that is equivalent to (mn) (x) is:
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7 0
4 years ago
Read 2 more answers
Water is leaking out of an inverted conical tank at a rate of 12,000 cm3/min at the same time that water is being pumped into th
Bas_tet [7]

Answer:

291111.1cm^3/min

Step-by-step explanation:

We are given that

\frac{dV}{dt}_{out}=12000 cm^3/min

Height of tank,h=6 m

Diameter of top,d=4 m

Radius,r=\frac{d}{2}=\frac{4}{2}=2 m

\frac{dh}{dt}=20 cm/min

\frac{r}{h}=\frac{2}{6}=\frac{1}{3}

r=\frac{1}{3} h

We have to find rate at which water is being pumped into the tank.

Volume of conical ,V=\frac{1}{3}\pi r^2 h

V=\frac{1}{3}\pi(\frac{1}{3} h)^2h=\frac{1}{27}\pi h^3

\frac{dV}{dt}=\frac{1}{9}\pi h^2(\frac{dh}{dt})

h=2 m=200 cm

1m=100 cm

\frac{dV}{dt}_{in}-12000=\frac{1}{9}\pi(200)^2\times 20

\frac{dV}{dt}_{in}=12000+\frac{1}{9}\pi (40000)\times 20

\frac{dV}{dt}_{in}=291111.1cm^3/min

4 0
3 years ago
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