1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lbvjy [14]
3 years ago
15

What is the x-intercept of the graph y = 2x - 14? -14 -7 0 7

Mathematics
1 answer:
shusha [124]3 years ago
5 0

Answer:

the answer is -7

You might be interested in
I have no clue how to do this. I just need to pass my online math class.
Lerok [7]
If F(3) then 3=x. So all you would do is substitute 3 in for x
3 0
3 years ago
Read 2 more answers
3.) mr. smith’s class sold wrapping paper for $3.50 each and mr. davis’ class sold magazines for $2.75 each. together, the class
igor_vitrenko [27]

Answer:

The number of wrapping paper sold was 32 and the number of magazines sold was 40

Step-by-step explanation:

Let

x ----> the number of wrapping paper sold

y ----> the number of magazines sold

we know that

The classes sold 72 items

so

x+y=72 ----> equation A

The classes earned $222 for their school

so

3.50x+2.75y=222 ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

using a graphing tool

The solution is (32,40)

see the attached figure

therefore

The number of wrapping paper sold was 32 and the number of magazines sold was 40

7 0
3 years ago
The figure is made up of a hemisphere and a cylinder.
Goryan [66]
Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: \pi \approx 3.14
V (volume) = ?

Solving:(<span>Cylinder volume)
</span>V = h* \pi *r^2
V = 8*3.14*5^2
V = 8*3.14*25
\boxed{ V_{cylinder}  = 628\:cm^3}

<span>Note: Now, let's find the volume of a hemisphere.
</span>
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4 * \pi *  \frac{r^3}{3}, but we have a hemisphere, so the formula will be half the volume of the hemisphere V =  \frac{1}{2}  * 4 * \pi *  \frac{r^3}{3} &#10;

Formula: (<span>Volume of the hemisphere)
</span>V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}

Solving:
V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{5^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{125}{3}
V =  \frac{1570}{6}
\boxed{V_{hemisphere}\approx 261.6\:cm^3}


<span>Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)
</span>
Volume of the figure = cylinder volume + hemisphere volume
Volume of the figure = 628 cm³ + 261.6 cm³
\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark
3 0
3 years ago
Read 2 more answers
Determine whether each equation represents a proportional relationship.<br> y=2.5x<br> y=x−4
mamaluj [8]

Answer:

yes

no

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
I need help ASAP please
Rom4ik [11]

Answer:

Use photomath

Step-by-step explanation:

sorry it doesnt answer your question but just use it it's free and great

7 0
2 years ago
Other questions:
  • If a cubic yard of sand weighs 1.5 (US) tons, how many 11x6x7 inch ammo boxes can be completely filled with 1 ton of sand?
    15·1 answer
  • Please Help!!!
    12·1 answer
  • Will 6,8, and 14 form a triangle
    13·1 answer
  • (30 POINTS!!!) Suppose △ABC≅△LMN .
    7·2 answers
  • 51, 16, 7, 8, 54, 25, 7, 36, 51 - what is the range?
    6·2 answers
  • How much do you need to subtract from 31/6 to make 5
    14·1 answer
  • What are the two ways to determine if something is a function
    15·2 answers
  • The sum of two and four and six times eight?
    14·2 answers
  • Billy had a farm with chickens, goats and cows. He wanted to know how many animals he had altogether, so he placed them in group
    6·1 answer
  • Raj had 12 gallon of orange juice. He used ​89 of the juice to make punch.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!