Answer: B
Negative a squared b and 5 a squared b
Step-by-step explanation:
Given that:
Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,
- a^2b + 6ab - 8 + 5a^b - 6a - b
Collecting the like term by rearranging the expression
5a^2b - a^2b + 6ab - 6a - b
The like terms in the expression above are
5a^2b - a^2b.
The correct option is B:
Negative a squared b and 5 a squared b or (-a^2b and 5a^b)
6w-y=2z
6w=2z+y
w=(2z+y):6
w=(z:3)+(y:6)
16 because 5 times 4 = 20 there for you multiply 4 times 4 to get 16
I believe the answer is 0=1
Find rates of change until you find a constant.
dy/dx=1,2,3,4,5,6
d2y/dx2=1,1,1,1,1
So the acceleration, d2y/d2x, is constant. This means that this is a quadratic sequence of the form a(n)=an^2+bn+c. So we can set up a system of equations to solve for the values of a,b, and c. Using the first three points, (1,1), (2,2), and (3,4) we have:
9a+3b+c=4, 4a+2b+c=2, and a+b+c=1 getting the differences...
5a+b=2 and 3a+b=1 and getting this difference...
2a=1, so a=1/2 making 5a+b=2 become:
2.5+b=2, so b=-1/2, making a+b+c=1 become:
1/2-1/2+c=1, so c=1 so the rule is:
a(n)=0.5x^2-0.5x+1 or if you prefer to not have decimals
a(n)=(x^2-x+2)/2
