-.3 0.5 .55 -.35 least to greatest

Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com

Ymorist [56]

Answer:

a) $183-1.984\frac{20}{\sqrt{100}}=179.032$

$183+1.984\frac{20}{\sqrt{100}}=186.968$

So on this case the 95% confidence interval would be given by (179.032;186.968)

b) $190-1.984\frac{23}{\sqrt{100}}=185.437$

$190+1.984\frac{23}{\sqrt{100}}=194.563$

So on this case the 95% confidence interval would be given by (185.437;194.563)

c) For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Part a : Summer

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=100-1=99$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that $t_{\alpha/2}=1.984$

Now we have everything in order to replace into formula (1):

$183-1.984\frac{20}{\sqrt{100}}=179.032$

$183+1.984\frac{20}{\sqrt{100}}=186.968$

So on this case the 95% confidence interval would be given by (179.032;186.968)

Part b: Winter

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=100-1=99$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that $t_{\alpha/2}=1.984$

Now we have everything in order to replace into formula (1):

$190-1.984\frac{23}{\sqrt{100}}=185.437$

$190+1.984\frac{23}{\sqrt{100}}=194.563$

So on this case the 95% confidence interval would be given by (185.437;194.563)

Part c

For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

5 0

3 years ago

The equation of a straight line is y+10=5x

MariettaO [177]

Answer:

y=5x-10

Step-by-step explanation:

y+10=5x

y=5x-10

4 0

4 years ago

Can someone help me (Geometry)

Vesnalui [34]

$x+x+4=72\\\\\Rightarrow2x=68\\\\\Rightarrow x=34$

4 0

3 years ago

HELP ME PLEASE!

shusha [124]

Answer:

Part A) The probability is closer to 0, because is less than 50%

Part B) The probability is closer to 1, because is greater than 50%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

so

Let

x------> size of the event space

y-----> size of the sample space

so

$P=\frac{x}{y}$

Part A) Is the probability of hitting the black circle inside the target closer to 0 or 1?

In this problem we have

x------> is the area of the black circle

y------> is the total area of the square target

Find the area of black circle

$r=3/2=1.5\ units$

$x=(3.14)(1.5)^{2} =7.065\ units^{2}$

Find the total area of the square target

$y=9^{2}=81\ units^{2}$

Find the probability

$P=\frac{7.065}{81}=0.0872$

Convert to percentage

$0.0872*100=8.72\%$

The probability is closer to 0, because is less than 50%

Part B) Is the probability of hitting the white portion of the target closer to 0 or 1?

In this problem we have

x------> is the area of the white portion of the target

y------> is the total area of the square target

Find the area of the white portion

The area is equal to the area of the square minus the area of the circle

$x=81-7.065=73.935\ units^{2}$

Find the probability

$P=\frac{73.935}{81}=0.9128$

Convert to percentage

$0.9128*100=91.28\%$

The probability is closer to 1, because is greater than 50%

4 0

3 years ago

What is the factored form of 2x3 + 4x2 – x?

AleksandrR [38]

Looking at the expression, we see that the only common factor shared between these three terms is x.

We factor out x:
x(2x2 + 4x - 1)

We can no longer find any common factors, so this is the final answer.

8 0

3 years ago

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