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2 years ago

Whic of the following are valid names for the triangle below? Check all that apply.

Mathematics

1 answer:

emmasim [6.3K]2 years ago

4 0

Answer:

A, C, E

Step-by-step explanation:

As long as all the 3 letters(D, K, and M) are included, it should be a valid name. These are the 3 points in the triangle afterall.

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Martin and Alexia are rock climbing each person's rate stays the same for the first hour they climb mountain climbers 3 1/3 mete

Minchanka [31]

1. If Martin climbs 3 1/3 meters in the first one 1/6 hour, then he climbs

$3\dfrac{1}{3}\cdot 6=\dfrac{10}{3}\cdot 6=20$ meters per hour. Then, option A is correct and options C and E are false.

2. If Alexia climbs 17 1/2 in the first 5/6 hour, then she climbs

$17\dfrac{1}{2}\cdot \dfrac{6}{5}=\dfrac{35}{2}\cdot \dfrac{6}{5}=21$ meters per hour and it takes Alexia $\dfrac{1}{21}$ of an hour to climb 1 meter. Then options B and D are correct and option F is false.

Answer: correct options are A, B and D.

7 0

3 years ago

A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The

Vladimir [108]

Using the Sine rule,

$\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}$ $\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}$

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

$A^0+P^0+B^0=180^0$ $\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}$

Using the side rule to find the length of wire BP,

$\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}$

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0

1 year ago

The second of two numbers is 4 less than twice the first. Their sum is 80.Find the numbers

Otrada [13]

The first number is x
the second number is 2x-4
combine both numbers = 80
x+2x-4=80
3x-4=80
3x=84
x=28
one number is 28 and the other is 52.

4 0

2 years ago

I need help solving this problem

Bad White [126]

Answer:

5.4

Explanation:

I multiplied 18.6 by the answer choices that should give me 100.44. But the shortcut to this is to divide the area by it’s height.

4 0

2 years ago

Gitta is asked to find the probability of getting all heads on 3 coin tosses. This is a compound event.

DedPeter [7]

1. P(getting all head)= $\frac{n(getting-all-head)}{n(Sample-space)}$

2. Event: getting all head can happen in only one way: HHH

3. n(Sample space) can be calculated by

a. counting, a good ways to organize counting is drawing a tree diagram, CHECK THE PICTURE

or
b. There are 2 possible outcomes each time we throw the dice so 2*2*2=8 is the total number of outcomes, that is the number of the sample space.

4. So finally P(getting all head)= $\frac{1}{8}$

3 0

3 years ago

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