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Marina86 [1]
3 years ago
7

Billy has 1 gallon of paint. He is going to pour it into a paint tray that measures 10 inches wide, 14 inches long, and 4 cm dee

p.
(1 gallon = 231 in3, 1 inch = 2.54 cm)
hich of the following scenarios will happen?
The paint will not fill the tray by 441 cm3.
The paint will not fill the tray by 10.53 in3.
The paint will fill the tray exactly.
The paint will overfill the tray by 10.53 in3.
Mathematics
1 answer:
polet [3.4K]3 years ago
5 0
Lets see if the gallon fill the paint tray or not.For that purpose we need to find out the volume of the paint tray and compare it with the volume of the gallon.Given:Length = 14 inchesWidth = 10 inchesDepth = 4 cm = 1.57 inches
Volume = length x width x depthVolume = 14 x 10 x 1.57             = 220.47 inches cubeVolume of Gallon = 231 inches cubeComparing the two volumes:231 inches cube - 220.47 inches cube = 10.52 inches cubeHence,The paint will not fill the tray by 10.53 in3.
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3/8 * 4 ____*____=_____=______
kirill [66]

Answer:

your answer is 1.5 150% or 3/2 there all the same anyway

Step-by-step explanation:

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3 years ago
Ms. Lapido bought a car and pay for it $20.000.At the end of 10 years the car has no value whatsoever. Assuming that the car is
Leviafan [203]

Answer:

A) the value of the car will be 13,333.34 after 3 years ( not sure )

B) the depreciation of the car will be 2222.22 per year ( not sure)

C)  i do not know

4 0
3 years ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
At Marco's school, 5/8 of the students are in the band. What percent of the students are in the band?
Harman [31]
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7 0
3 years ago
A train travels 146 miles in 2 hours. At this rate, how many miles will it travel in 3.5 hours?​
Svetllana [295]

Answer:

255.5 miles

Step-by-step explanation:

146 miles - 2 hours

x miles - 3.5 hours

Cross multiply

2x = 146 x 3.5

2x = 511

Divide both sides by 2

x = 511/2

x = 255.5 miles

7 0
3 years ago
Read 2 more answers
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