Answer:
1. y = 4x - 27
2. y = -4x - 15
Step-by-step explanation:
If two lines are parallel, then they have the same slope. So, the slope of the line we are looking for needs to be 4. We can start by writing a point-slope equation:
y - y1 = m(x - x1)
We can substitute the values we have, the point we are using is (8, 5) because it needs to be on the line:
y - 5 = 4(x - 8)
We can distribute:
y - 5 = 4x - 32
y = 4x - 27
We are not given the slope-intercept form, so we must divide both sides by two to get it:
y = 1/4 x + 8
A perpendicular line has the slope that is the negative reciprocal of the one that is given. So, the slope of the line would be - 4. We can start by writing a point-slope equation:
y - y1 = m(x - x1)
We can substitute the values we have, the point we are using is (-5, 5) because it needs to be on the line:
y - 5 = -4(x + 5)
We can distribute:
y - 5 = -4x - 20
y = -4x - 15
Answer:
(a) 120 choices
(b) 110 choices
Step-by-step explanation:
The number of ways in which we can select k element from a group n elements is given by:

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

Then each student have 120 possible choices.
On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:
1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:
50 + 50 + 10 = 110
Answer:
70%
Step-by-step explanation:
Total number of teenagers surveyed
12+20+38+20+10 = 100
Find the number of teenagers with 3 or fewer pairs of shoes
12+20+38 =70
P(3 or fewer) = teenagers with 3 or fewer/ total
= 70/100
= 70%
<span><span>If you would like to solve the equation </span>- 7 * x
- 3 * x + 2 = 8 * x - 8, you can calculate this using the following steps:<span>
- 7 * x - 3 * x
+ 2 = 8 * x - 8
- 7 * x -
3 * x - 8 * x = - 8 - 2
- 18 * x =
- 10 /(-18)
x = 10 / 18
x = 5/9
<span>The
correct result would be </span>5/9<span>.</span></span></span>