Answer:
All the possible zeroes of the polynomial: f(x) =
are ±1 , ±2 , ±4 , ±
, ±
, ±
by using rational zeroes theorem.
Step-by-step explanation:
Rational zeroes theorem gives the possible roots of polynomial f(x) by taking ratio of p and q where p is a factor of constant term and q is a factor of the leading coefficient.
The polynomial f(x) = ![3x^{6} + 4x^{3} - 2x^{2} +4](https://tex.z-dn.net/?f=3x%5E%7B6%7D%20%2B%204x%5E%7B3%7D%20-%202x%5E%7B2%7D%20%2B4)
Find all factors (p) of the constant term.
Here we are looking for the factors of 4, which are:
±1 , ±2 and ±4
Now find all factors (q) of the coefficient of the leading term
we are looking for the factors of 3, which are:
±1 and ±3
List all possible combinations of ±
as the possible zeros of the polynomial.
Thus, we have ±1 , ±2 , ±4 , ±
, ±
, ±
as the possible zeros of the polynomial
Simplify the list to remove and repeated elements.
All the possible zeroes of the polynomial: f(x) =
are ±1 , ±2 , ±4 , ±
, ±
, ±
Learn more about Rational zeroes theorem here -https://brainly.ph/question/24649641
#SPJ10