Consider the quadratic function y = 1/5(x - 2)2 + 5.

Mathematics

2 answers:

stellarik [79]3 years ago

7 0

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Hunter-Best [27]3 years ago

3 0

Answer:

Step-by-step explanation:

There are no real roots and the graph contains point (2,5). Notice it is in vertex form. So there must be a point at x = 2 and y = 5. However, if it is the vertex and it opens upwards, that means it cannot intersect the x axis. So 2 and 4 are the correct answers I believe.

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Reasoning point F lies on EG and point M lies on EN. If F,E, and M are collinear, what must be true of these rays.

almond37 [142]

This means that all of the points are co-linear. This is because if EG is a segment that contains F, and EN is a segment that contains M, then there can be two different segments. However, for a point F on the first segment and a point M on a second segment be in the same line as an end point of one of the segments, the segments have to be co-linear. They overlap.

6 0

3 years ago

Read 2 more answers

A group of 2 adults and 4 children spent $38 on tickets to a museum. A group of 3 adults and 3 children spent $40.50 on tickets

Anestetic [448]

Answer:

Looks like you gave the answer already.

a = 8 and c = 5.5

Step-by-step explanation:

2a + 4c = 38.00 --> x3 --> 6a + 12c = 144

3a + 3c = 40.50 --> x2 --> 6a + 6c = 81

6c = 33