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ozzi
3 years ago
10

Jack plays cards with friend each afternoon here are his scores from the last 5 games 8,-6,-3,4,7 which is the least of his scor

es
Mathematics
1 answer:
vlada-n [284]3 years ago
6 0

Answer:

-6

Step-by-step explanation:

8,-6,-3,4,7 rearranged in ascending order produces -6, -3, 4, 7, 8.

-6 is the least of these scores (i. e., -6 is the lowest score).

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1707 I think if I did it right

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3 years ago
Select the statements that are true about the graph.
torisob [31]

Answer:It's called the "y intercept" and it's the y value of the point where the line intersects the y- axis. For this line, the y-intercept is "negative 1." You can find the y-intercept by looking at the graph and seeing which point crosses the y axis. This point will always have an x coordinate of zero.

Step-by-step explanation:

The Y intercept of a straight line is simply where the line crosses the Y axis.

Example

Y intercept

In the above diagram the line crosses the Y axis at 1.

The Y intercept is equal to 1 and the point is written as (0,1). Notice that for the y-intercept the x-coordinate of the point is always zero..

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3 years ago
What is the perimeter?<br> I’ll give you brainiest however you spell it
iren2701 [21]

Answer:

48

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
Suppose that the functions p and q are defined as follows.p(x) = -2x + 1q(x)=-x?Find the following.
MariettaO [177]

First let us find

(q\mathrm{}p)(x)\begin{gathered} q(p(x))=q(-2x+1) \\ =-(-2x+1)^2 \\ So\text{ } \\ (q\mathrm{}p)(5)=-(-2\times5+1)^2 \\ =-(9)^2 \\ =-81 \end{gathered}

Now let;s solve the second part

\begin{gathered} (p\mathrm{}q)(x)=p(q(x)) \\ =p(-x^2) \\ =-2(-x^2)+1 \\ =2x^2+1 \\ So\text{ (p.q)(5) will be } \\ (p\mathrm{}q)(5)=2(5)^2+1 \\ =51 \end{gathered}

6 0
1 year ago
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