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2 years ago

Which of the following is a point on the graph of y = (1/2)x?

Mathematics

1 answer:

kolezko [41]2 years ago

6 0

Answer:

The point on a function are the true values of the function.

Step-by-step explanation:

is a point on the graph of

The function is given as:

This means that:

x = 0, and y = 0

So, we have:

The above is not true, because:

This means that:

x = 0, and y = 1/2

So, we have:

The above is not true, because:

This means that:

x =2, and y = 1/4

So, we have:

The above is true.

Hence,

is a point on the graph of

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Hector wants to practice piano 2 hours each day. He practices piano for 3/4 hour before school and 7/10 hour when he gets home.

daser333 [38]

Answer:

me too

Step-by-step explanation:

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3 years ago

Can you look at this please what is the value of a? What is the value of b?

Allushta [10]

Answer:

$\huge\boxed{a=36;\ b=-9}$

Step-by-step explanation:

$(6x-3)(6x+3)=ax^2+b\qquad|\text{use}\ (a-b)(a+b)=a^2-b^2\\\\(6x)^2-3^2=ax^2+b\\\\6^2x^2-9=ax^2+b\\\\36x^2-9=ax^2+b\Rightarrow a=36;\ b=-9$

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3 years ago

In a certain Algebra 2 class of 27 students, 18 of them play basketball and 16

Bogdan [553]

Answer:

The probability is 0.89 or 89%

Step-by-step explanation:

Probability

There are n=27 students in a certain Algebra 2 class. 18 out of them play basketball and 16 of them play baseball.

We also know 3 students play neither sport. This leaves 27-3=24 students playing sports.

The probability that a randomly chosen student plays basketball or baseball is:

$\displastyle p=\frac{24}{27}$

Simplifying:

$\displastyle p=\frac{8}{9}=0.89$

The probability is 0.89 or 89%

6 0

3 years ago

How to find the quotient of r and 12

arlik [135]

You have to give another number to get the answer to this question. I would be happy to answer this if you could give me that other number. This is not an equation.

8 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers