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Stolb23 [73]
3 years ago
13

Rewrite each expression using exponents (-19)(-19)(-19)(-19)(-19)

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

-19^5 or -19 to the fifth

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10. A video rental store charges a $20 membership fee and $2.50 for each video
Pavel [41]
Y= 2.50(x) + $20 is the linear equation

If 15 videos are rented
Y=2.50(15) + $20
Y= $57.50

67.50 = 2.50(x) + 20
19= x
19 videos were rented in 3 months
8 0
3 years ago
Use a separate sheet of paper to solve the system of inequalities by graphing. Use the graph to decide if the point (1, –1) is i
Lena [83]

Answer:

The answer is no though, the point (1,-1) is below both.

Step-by-step explanation:

So the two inequalities are y≤-3x+3 and 3x+8y≥3

With inequalities you have to know a few things.  First, when you graph you may have to use non solid lines.  for instance, if you had x<5, 5 would not be part of the answer because it is only answers less than 5.  so you represent this by making a dashed line that says "you cannot include values on this line".  Second, with algebra, if you multiply both sides by a negative it flips the inequality.  for instance -y > 54 you would multiply (or divide) by -1 and it would change to y < -54.  Third, when graphing an inequality, treat it like an equation and graph the line as if it were said equation(with solid or dashed lines as needed)  then, if it is y > f(x) you shade in the section above the line and y < f(x) shades in below.  The shaded part is your answer basically.  Now lets get into yours.

y≤-3x+3

It is already in the form y = f(x)  so grapht he line 3x + 3 with a solid line since it is y is less than or equal to,  then shade below that line.  

3x+8y≥3

First get it so y is by itself

3x+8y≥3

8y≥3 - 3x

y ≥ 3/8 - 3/8 x

Now grapht his line  with a solid line and shade the area above it.

Now, the shaded area below between y ≥ 3/8 - 3/8 x and  y≤-3x+3 and the lines are your answer, so you need to check if the point (1, -1) is in this shared shaded area or on one of the lines.

The answer is no though, the point (1,-1) is below both.

6 0
3 years ago
PLEASE HELP ASAP!!!!!
padilas [110]

Answer:

A'''(1,1), B'''(-2,-1) and C'''(-4,0).

Step-by-step explanation:

Triangle ABC has vertices with coordinates A(-6,-1), B(-3,-3) and C(-1,-2) (from given diagram).

1. Translation the triangle ABC 5 units to the right and 2 units up has a rule

(x,y)→(x+5,y+2).

Then the image triangle A'B'C' has vertices A'(-1,1), B'(2,-1) and C'(4,0).

2. Reflection the triangle A'B'C' across the line y=-x has a rule

(x,y)→(-y,-x).

Then the image triangle A"B"C" has vertices A"(-1,1) (this point lie on the line), B"(1,-2) and C"(0,-4).

3. Rotation the triangle A"B"C" counterclockwise about the origin by 270° has  a rule

(x,y)→(y,-x).

Then the image triangle A'''B'''C''' has vertices A'''(1,1), B'''(-2,-1) and C'''(-4,0).

3 0
3 years ago
Read 2 more answers
96743 divided by 25 im at school in person so uh ya lol
mash [69]

Answer:

3,869.72

Step-by-step explanation:

5 0
3 years ago
Can you guys graph a system of equations and make sure it has two parabolas with the same vertex and a line that crosses the sam
Andrews [41]

Answer:

Sketch the following three graphs:

1) y = (x - 5)²

2) y = -(x - 5)²

3) y = x - 5

First two are parabolas with vertex at (5,0)

Third one is a line which intersects both the parabolas as (5,0)

6 0
3 years ago
Read 2 more answers
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