The first graph is linear and the 2nd one is nonlinear
the first table goes for linear and the 2nd table goes for nonlinear :)
Answer:
The speed rate of the plane in still air is 1006.67 km/h
The speed rate of the wind is 246.67 km/h
Step-by-step explanation:
To answer the question, we let the speed of the plane in still air = x km/h
Let the speed of the wind = y km/h
Therefore,
4560/(x - y) = 6 hours and
3720/(x + y) = 3 hours
4560 = 6·x - 6·y.........(1)
3720 = 3·x + 3·y ........(2)
Multiplying equation (2) by 2 and add to (1) gives
12080 = 12·x
x = 12080/12 =
km/h
Substituting the value of x in (1) gives
4560 = 6040 - 6·y
6·y = 1480
y = 1480/6 = 
The speed rate of the plane in still air = 1006.67 km/h
The speed rate of the wind = 246.67 km/h.
Answer:
m=0.833333
Step-by-step explanation:
(1/16)−3m+1=64
log((1/16)−3m+1)=log(64)
(Take log of both sides)
(−3m+1)*(log(1/16))=log(64)
−3m+1=log(64)
log(1/16)
−3m+1=−1.5
−3m+1−1=−1.5−1
(Subtract 1 from both sides)
−3m=−2.5
−3m
−3
=
−2.5
−3
(Divide both sides by -3)
Answer:
7 buses. 52÷ 8 = 6.5 so rounding up to 7
0.3 repeating is greater than 0.083