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andreev551 [17]
2 years ago
5

Flora made 7 withdrawals of $75 each from her bank account. How much did she withdraw in total?

Mathematics
1 answer:
Sliva [168]2 years ago
8 0

75$ times 7      that is 525

$525

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Please help me! ASAP!!!!!
Greeley [361]

Answer:

x=36

Step-by-step explanation:

17+3 =20

now we have :

x+4

___         = 20

  2

20*2= 40

x+4=40

x=36

hopes this helps

4 0
2 years ago
One number is 6 greater than another. the product of the number is 55. find the numbers
Basile [38]
Here's how to do this problem:

6+ x= 55
-6       -6
x=49
5 0
3 years ago
Solve for the base. Round to hundredths when necessary.
Elena-2011 [213]

Answer:

  1. 2730.54
  2. 18.8%
  3. 62.5% (decrease)

Step-by-step explanation:

The applicable formula is ...

  rate = portion/base

so ...

  base = portion/rate

Of course, a percentage is a fraction that has been multiplied by 100%.

__

1. base = portion/rate = 456/0.167 ≈ 2730.54

The base is about 2730.54.

__

2. rate = portion/base = 50/266 ≈ 0.18797 ≈ 18.8%

The rate is about 18.8%.

__

3. The decrease can be figured from ...

  rate of change = (new amount)/(original) -1 = 33/88 -1

     = -5/8 = -0.625 = -62.5%

The rate of decrease is 62.5%.

6 0
3 years ago
Stephanie wants to make 22.5 qt. of a 20%
aivan3 [116]

Answer:

y = 10.5qt

x = 12 qt

Step-by-step explanation:

0.6x+ 0.36y = 22.5 * 0.2

0.06x + 0.36y = 4.5

x + y = 22.5

x = 22.5 - y

0.06(22.5 - y) + 0.36y = 4.5

1.35 - 0.06y + 0.36y = 4.5

0.3y = 4.5 - 1.35

0.3y = 3.15

y = 3.15 / 0.3

y = 10.5 qt

x = 22.5 - y

x = 22.5 - 10.5

x = 12 qt

3 0
2 years ago
The administrator of a nursing home would like to do a time-and-motion study of staff time spend per day performing nonemergency
WINSTONCH [101]

Answer:

32 days must be sampled to test the proposed hypothesis.

Step-by-step explanation:

Consider the provided information.

The average number of person-hours per day spent on these task was \mu_0=16.

The actual value of μ is 12 hours or less i.e μ=12

She wants a test having α=0.05

The probability of a type II error of at most β=0.10 and σ=7.64.

δ = μ-μ0

   = 12-16

  = -4

Now use the formula for calculating the sample size:

N=\frac{(Z_{\alpha}+Z_{\beta})^2\sigma^2}{\delta^2}

Substitute the respective values.

N=\frac{(Z_{0.05}+Z_{0.1})^2(7.64)^2}{(-4)^2}

N=\frac{(1.6449+1.2816)^2(7.64)^2}{16}

N=31.2437958482\approx 32

Hence, 32 days must be sampled to test the proposed hypothesis.

5 0
3 years ago
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