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r-ruslan [8.4K]
3 years ago
8

In Nancy's class, 11/18 of the girls have brown eyes, 2/9 of the girls have blue eyes, and 1/6 of the girls have hazel eyes. Wha

t fraction of the girls have more brown eyes than hazel eyes? [Note: Write your answer in simplest form.]
A. 1/18
B. 7/18
C. 5/6
D. 4/9
Mathematics
2 answers:
brilliants [131]3 years ago
8 0
11/18- 3-18 equal 8/18. Divide by 2
4/9
Answer d
alukav5142 [94]3 years ago
7 0
It would be: 11/18 - 1/6

= 11 - 3 / 18

= 8/18

= 4/9

In short, Your Answer would be Option D

Hope this helps!
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ikadub [295]

a) The probability  that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is  0.1714.

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Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show  = 0.7   ⇒ P(J) = 0.7

Probability that Jane watches a certain show  = 0.3   ⇒ P(Je) = 0.3

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 = 0.4   ⇒ P(J/Je) = 0.4

a. )  Here, we need to find the probability of  both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

P(J/Je)  = \frac{P(J \cap Je)}{P(Je)}

\implies  0.4  = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3  = 0.12

Hence the probability  that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

P(Je/J)  = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J)  = \frac{0.12}{0.7}  = 0.1714

Hence, the probability that Jane watches the show, given that John does is  0.1714.

c) As we can see P(Jane ∩ John) =  0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12  = 0.88

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3 years ago
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