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Tems11 [23]
2 years ago
7

in the number 40.9113,how does the value of 1 in hundredths place compare to the value of 1 in the thousandths place ???

Mathematics
2 answers:
zalisa [80]2 years ago
8 0
1 in the hundredths place is smaller to the value of 1 in the thousands place. They both are behind the decimals also.
gizmo_the_mogwai [7]2 years ago
5 0
The 1 in the hundredths place is ten times bigger in value than the 1 in the thousandths place.
1/100 = 1/1000 x 10
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Maya runs 7 miles in 60 minutes. At the same rate, how many miles would she run in 24 minutes
Scilla [17]

Answer:

2.8 miles

Step-by-step explanation:

2.8 miles or minutes

3 0
3 years ago
Someone plz help with this!
Murljashka [212]

Answer:

15x-2+7x+4=90°[being complementary angle]

22x+2=90°

22x=90°-2

22x=88

x=88/22

x=4

8 0
2 years ago
Find the value of x³+ y³ + z³ – 3xyz if x² + y² + z² = 83 and x + y + z = 15​
raketka [301]

identity used is

x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).

then use

(x+y+z)² = x²+y²+z²+2(xy+yz+xz)

225= 83 + 2(xy+yz+xz)

xy+yz+xz = (225-83)/2

xy+yz+xz= 142/2

xy+yz+xz= 71

ok

now use identity

x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).

now

x³ + y³+ z³– 3xyz = 15 (83 – xy – yz – zx).

= 15[83 - (71)]

= 15×12

=180

4 0
3 years ago
Please Help! Ratio question!
klio [65]

Answer:

10

Step-by-step explanation:

divide 1800 by 20 and 1800 by 18 and find the difference

4 0
3 years ago
Read 2 more answers
Can u guys PLEASE answer this question ASAP. A fat cat that was initially 12 kg reduces its weight by 10% each month. How long d
Mkey [24]

Answer:

It takes at least 7 months for the cat to be at least 6 kg lighter than the original weight.

Step-by-step explanation:

Use exponential decay formula:

A = P (1-r)t

A = amount decreased to

P = original amount

r = rate of decrease

t = time

 

6 ≥ 12 (1-0.10)t      divide both sides by 12

0.5 ≥ (0.9)t            take log of both sides

log (0.5) ≥ log (0.9)t     power rule of logs lets the exponent t drop to front of log to become a factor

log (0.5) ≥ t log(0.9)     divide both sides by log(0.9) which is negative so reverse the inequality sign

log (0.5) / log (0.9) ≤ t     use calculator

6.57 ≤ t

 

It takes at least 7 months for the cat to be at least 6 kg lighter that original weight.

 

check:

12 (0.9)7≈ 5.73

12 (0.9)6 ≈ 6.37

5 0
3 years ago
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