Answer:
D. It is on the angle bisector of ∠BAC
Step-by-step explanation:
Given that point Q is equidistant from AB and AC. This implies that AB and AC forms an angle BAC i.e <BAC. An equidistant point is a point that has the same distance from two different reference points.
Bisection is the process by which a line or angle is divided into two equal parts. A line that passes through the point of division is called a bisector, which is of equal distance to either of the reference points.
Thus by construction, a point that would be of equal distance to AB and AC is on an angle bisector of <BAC. So that point Q is on the angle bisector of <BAC.
Answer:
The answer is 50
Step-by-step explanation:
= -3(-2-3×6)-5{4+2(-1)}
= -3(-2-18)-5{4-2}
= -3(-20)-5{2}
= 60-10
= 50
Answer:
1/(x^(17/12)y^(5/3))
Step-by-step explanation:
We assume you want to simplify the expression. The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
Using these "all at once", we can add up the exponents of each of the variables:
x^(-2/3 -2·0 -(1/2)(3/2))·y^(-2/3-(1/2)·2) = x^(-2/3-3/4)y^(-2/3-1)
= x^(-17/12)y^(-5/3)
= 
Answer:
6 and 7 for the square root or 38 and 40 im not sure on which by the wording being very low standard
