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ValentinkaMS [17]
3 years ago
5

Is 4/3 is <,>, or = to 6/5 plz me help!!!!!!

Mathematics
2 answers:
sukhopar [10]3 years ago
7 0
Well, you need to first find a common denominator for the two fractions. In this case, a common denominator would be 15. Multiply the first equation by 5 and the second by 3.
4/3*5=20/15
6/5*3=24/15
And as we can see by the answers we got that 4/3<6/5
Hope it helps!
-Lacy
tino4ka555 [31]3 years ago
4 0
It would be > (greater than sign). If you need how I got this answer, you could ask me.. :)
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4 0
3 years ago
one batch of cookies makes 24 cookies. the recipe calls for 1 3/4 cups of flour. if Sarah needs to make 60 cookies how much flou
Svetllana [295]

Answer:

4 3/8 cups of flour needed for 60 cookies

Explanation:

You can multiply 24 by 2.5 to get 60 so you'd multiply the cups of flour by 2.5 as well. You multiply both of them by the same number because it's a ratio. You'd multiply then simplify to get the answer 4 3/8 cups of flour.

7 0
3 years ago
Find the quotient. 12a^3p^4 ÷ -2a^2p
777dan777 [17]

Answer:

-(6ap³)

Step-by-step explanation:

We have to find the quotients of

\frac{12a^{3}p^{4}}{-2a^{2}p}

We take the common 2a² p from the numerator

= \frac{(6ap^{3}(2a^{2}p))}{(-2a^{2}p)}

= -(6ap³)

Therefore, the quotient after division will be -(6ap³)

4 0
3 years ago
If the units digit of the three-digit positive integer k is nonzero, what is the tens digit of k ?
Vanyuwa [196]

Answer:

  any digit 0 to 9

Step-by-step explanation:

Nothing about your description of the number suggests that the 10s digit depends on the units digit. The tens digit can be any digit 0 to 9.

8 0
3 years ago
The GCD(a, b) = 9, the LCM(a, b)=378. Find the least possible value of a+b.
denis-greek [22]
\mathrm{gcd}(a,b)=9\implies9\mid a\text{ and }9\mid b\implies9\mid a+b

which means there is some integer k for which a+b=9k.


Because 9\mid a and 9\mid b, there are integers n_1,n_2 such that a=9n_1 and b=9n_2, and


\mathrm{lcm}(a,b)=\mathrm{lcm}(9n_1,9n_2)=9\mathrm{lcm}(n_1,n_2)=378\implies\mathrm{lcm}(n_1,n_2)=42

We have 42=2\cdot3\cdot7, which means there are four possible choices of n_1,n_2:

1, 42
2, 21
3, 14
6, 7

which is to say there are also four corresponding choices for a,b:

9, 378
18, 189
27, 126
54, 63

whose sums are:

387
207
153
117

So the least possible value of a+b is 117.
6 0
3 years ago
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