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Nuetrik [128]
4 years ago
10

Find one positive and one negative angle coterminal with an angle of

id="TexFormula1" title="\frac{11pi}{8}" alt="\frac{11pi}{8}" align="absmiddle" class="latex-formula">.
idk how to do the pi sign
Mathematics
1 answer:
zaharov [31]4 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Co terminal angles are angle ± 2π, that is

\frac{11\pi }{8} + 2π

= \frac{11\pi }{8} + \frac{16\pi }{8} = \frac{27\pi }{8}

and

\frac{11\pi }{8} - 2π

= \frac{11\pi }{8} - \frac{16\pi }{8} = - \frac{5\pi }{8}

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Drupady [299]
90 or something so yeah
3 0
4 years ago
A rectangular field is to be enclosed by a fence and divided
Phantasy [73]

Answer:

80000 square meters

Step-by-step explanation:

perimeter + dividing fence = 800

let a = length

let b = width

let c = length of dividing fence

perimeter = 2*a + 2*b

let's say...

c is the same as the length

2a + 2b + c = 800

2a + 2b + a = 800

3a + 2b = 800

area = length*width

area = a*b

area / b = a

3*(area/b) + 2b = 800

3*(area/b) = 800 - 2b

area/b = (800 - 2b)

area = (800 - 2b)*b

To make the area large, we make the right hand side large.

800b - 2b^2

If you put in terms of x, y it looks like a downward opening parabola, so the max area is at the vertex. Half way between the roots.

y = -2x^2 + 800x

y = -x^2 + 400x

0 = x*(-x + 400)

roots are x= 0 and x = 400

vertex is at x, aka b = 200

area at b=200 is (800 - 400)*200 = 80000

and a is area/b... 80000/400 = 200

5 0
3 years ago
When a jug is half-filled with marbles, it weighs 2.6 kg. If the jug weighs 4 kg when full, find the weight of the empty jug.
Soloha48 [4]

Let x be the jug, \frac{1}{2} for half-filled, y for the weight of the jug when empty.

∵ \frac{1}{2}x + y = 2.6 kg

∵ x = 4 kg

∴ \frac{1}{2} ⋅ 4 + y = 2.6 kg

∴ 2 + y =2.6 kg

∵ y = 2.6 - 2 = 0.6 kg

∴ The weight of the empty jug = 0.6 kg


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3 years ago
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