Question

Slope of -8,4 and 3,-4

Answer 1

For this case we have that by definition, the slope of a line is given by:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

Where:

$(x_ {1}, y_ {1})$and$(x_ {2}, y_ {2})$are two points through which the line passes

According to the statement we have:

$(x_ {1}, y_ {1}): (- 8,4)\\(x_ {2}, y_ {2}) :( 3, -4)$

Substituting we have:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-4-4} {3 - (- 8)} = \frac {-8} {3 + 8} = \frac {-8} {11} = - \frac {8} {11}$

Thus, the slope of the line is:

$m = - \frac {8} {11}$

Answer:

$m = - \frac {8} {11}$