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poizon [28]
3 years ago
14

NEED HELP!

Mathematics
1 answer:
MissTica3 years ago
6 0

Answer:

The rate of change is  

6.2  ×  10^{-3}   ms^{-1}  =  0.37 \frac{m}{min}  

Answer ^ ^ ^ ^ ^ ^ ^

Explanation: it broke itself

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Find the slope of the line y = 5x + 4.
avanturin [10]

Answer:

x=1/5y+−4/5

Step-by-step explanation:

Let's solve for x.

y=5x+4

Step 1: Flip the equation.

5x+4=y

Step 2: Add -4 to both sides.

5x+4+−4=y+−4/5x=y−4

Step 3: Divide both sides by 5.

5x/5=y−4/5x=1'5y+−4'5

Answer:

x=1/5y+−4/5

( I hope this was helpful) >;D

6 0
3 years ago
You play a game that involves drawing two numbers from a hat. There are 25 pieces of paper numbered 1 to 25 in the hat. Each num
Sergeu [11.5K]

Answer:so it’s 5

Step-by-step explanation:

It’s 2 divided by 10 = 5

3 0
3 years ago
Which of the following equations have no solution? Select all that apply.
lana [24]
The answer should be B and A
3 0
3 years ago
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The figure here shows triangle AOC inscribed in the region cut from the parabola y=x^2 by the line y=a^2. Find the limit of the
aleksandrvk [35]
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =

(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =

= 2a^3 - 2(a^3)/3 = [4/3](a^3)

Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3

ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =

Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
 



3 0
3 years ago
Area and perimeter pls
Alla [95]

Perimeter 97.24

90 + 5 + 2.25

Area 1008

90 * 5 * 2.24 = 1008

3 0
3 years ago
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