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stira [4]
3 years ago
15

Case 4 – House Price. A small data set contains information on House Price (Y) in dollars, as well as predictors: number of Cars

the garage can hold (X1), the Age of the house in years (X2), and the number of Rooms in the house (X3). Consider the regression output below and determine the missing values A through F. Dependent variable is: Price R squared = AAAA R squared (adjusted) = 57.3% s = BBBB with 22 - 4 = 18 degrees of freedom Source Sum of Squares df Mean Square F-ratio Regression 6892069096 DDDD 2297356365 CCCC Residual 3975520758 18 220862264 Variable Coefficient s.e. of Coeff t-ratio prob Constant -26737.5 21074 -1.27 0.2207 Cars 6185.10 6640 0.932 0.3639 Age -333.303 757.8 EEEE FFFF Rooms 11154.6 2524 4.42 0.0003
KEY:
(A) = 63.4%
(B) = 14861
(C) = 10.4
(D) = 3
(E) = –0.44
(F) = 0.66

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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The area of the shaded region of circle O is 9π m2
blsea [12.9K]
For full circle area is π * R² [here R = radius],
for a sector of circle with angle β, area will be = (β/2) * R², β is in radian,
here let β = 22.5° = (π * 22.5/180) = π/8 radian,
now [(π/8)/2] * R² = 9π, [π/16] * R² = 9π
R² = 9 * 16 = 144, 
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5 0
3 years ago
A certain car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation A pizza delivery company buys
zubka84 [21]

Answer:

z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028

z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441

An we can use the normal standard table and the following difference and we got this result:

P(-1.028

Step-by-step explanation:

Assuming this statement to complete the problem "with a standard deviation 5 mpg"

We have the following info given:

\mu = 34 represent the mean

\sigma= 5 represent the deviation

We have a sample size of n = 54 and we want to find this probability:

P(33.3 < \bar X< 34.3)

And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

And we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028

z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441

An we can use the normal standard table and the following difference and we got this result:

P(-1.028

7 0
3 years ago
-1/3 + 7/4. in simplest form plzz
Goryan [66]
Greatest Common Factor: 12-1/3 = -4/12, 7/4 = 21/12-4/12 + 21/12 = 17/12
Answer in simplest form: 17/12
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825 - 625i

Hope it’s right
Best luck with your studying
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2 years ago
What is the nearest tenth P(4,-2) Q (1,3)
irinina [24]
I hope this helps you

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