Question

When volleyballs are purchased, they are not fully inflated. a partially inflated volleyball can be modeled by a sphere whose volume is approximately 180?

Answer 1

I added a screenshot with the complete question.

Answer:
The radius increased by 0.6 in

Explanation:
1- getting the radius before the ball is fully inflated:
volume of sphere = $\frac{4}{3} \pi r^3$

We are given that the volume before the ball is fully inflated is 180 in³. Therefore, we can solve for the radius as follows:
180 = $\frac{4}{3} \pi r^3$
135 = π * r³
42.9718 = r³
radius = 3.5026 in

2- getting the radius after the ball is fully inflated:
volume of sphere = $\frac{4}{3} \pi r^3$

We are given that the volume after the ball is fully inflated is 294 in³. Therefore, we can solve for the radius as follows:
294 = $\frac{4}{3} \pi r^3$
220.5 = π * r³
70.187 = r³
radius = 4.124958 in

3- getting the increase in the radius:
increase in radius = radius after inflation - radius before inflation
increase in radius = 4.124958 - 3.5026
increase in radius = 0.622 which is approximately 0.6 in

Hope this helps :)