Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.
The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.
we know that
1 hour is--------> 60 minutes
1 minute is---------> 60 sec
so
10 hour =10*60=600 minutes
39 sec=39/60=0.65 min
10 h 39 sec=600+0.65=600.65 min
therefore
<u>the answer is</u>
600.65 minutes
7x+9 equal 10 because it is equal to 5,
