1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KATRIN_1 [288]
3 years ago
13

What’s the answer?????????????????????

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0

Gradient = y/x

Gradient = 7--2/7-4 = 9/3 = 3

Gradient = 3x

We're looking for a gradient that's double 3x

6x

<h2>A. y = 6x + 1</h2>
You might be interested in
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}&#10;\qquad\qquad &#10;cos(\theta)=\cfrac{adjacent}{hypotenuse}&#10;\\\\\\&#10;% tangent&#10;tan(\theta)=\cfrac{opposite}{adjacent}&#10;\qquad \qquad &#10;% cotangent&#10;cot(\theta)=\cfrac{adjacent}{opposite}&#10;\\\\\\&#10;% cosecant&#10;csc(\theta)=\cfrac{hypotenuse}{opposite}&#10;\qquad \qquad &#10;% secant&#10;sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}&#10;\qquad\qquad &#10;cos(\theta)=\cfrac{\sqrt{35}}{6}&#10;\\\\\\&#10;% tangent&#10;tan(\theta)=\cfrac{-1}{\sqrt{35}}&#10;\qquad \qquad &#10;% cotangent&#10;cot(\theta)=\cfrac{\sqrt{35}}{1}&#10;\\\\\\&#10;sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}&#10;\\\\\\&#10;sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
4 years ago
solve for x and round to the nearest tenth. this is geometry. I will mark Brainliest. please help &lt;3
Amiraneli [1.4K]

Answer:

x= 41.8°

Step-by-step explanation:

use inverse trig to find x.

sin^{-1}(\frac{4}{6})=x

type this into your calculator. (make sure the mode on your calculator is degree or it won't work)

x= 41.8

Hope This Helps:)

brainliest please

5 0
3 years ago
Integral sqrt(4+3x) dx
Alisiya [41]
Let 4 + 3x = u

then 3dx = du
 
or, <span>1/3∫<span>u√</span>du
</span> 
= <span>1/3<span>u^<span>3/2</span></span>/(3/2)
</span> 
= <span>2/9∗(4+3x<span>)^<span>3/2

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span></span></span>
3 0
4 years ago
5x+7y=31 2x+4y=16 Which of the following systems could be used to solve the given system of equations by the addition method? 10
Pani-rosa [81]
Equation 1: 5x+7y=31
Equation 2: 2x+4y=16

We can either use the 'elimination' method or the 'substitution' method to solve this simultaneous equation.

In some cases one method is easier to use than the other. For this one, it would be easier to use the elimination method

We need to eliminate either the 'x' or the 'y' to begin with. Say we want to eliminate the 'x' terms, then the next step is to make the constant the same

Equation 1: the constant of 'x' is 5
Equation 2: the constant of 'x' is 2

To make the two constants the same, think of common multiple. The lowest common multiple for 5 and 2 is 10

Equation 1:  Multiply all terms by 2 to achieve 10x
Equation 2: Multiply all terms by 5 to achieve 10x

Equation 1: 10x+14y=62
Equation 2: 10x+20y=80

Once the constant of 'x' is the same, then we can start the elimination process. Since our aim is to eliminate, one of the 'x' need to be in negative form. We can either multiply Equation 1 or Equation 2 by (-1)

Equation 1: -10x - 14y = -62
Equation 2: 10x + 20y = 80

Hence the correct answer is: Third option




3 0
4 years ago
Round these numbers to the nearest ten and 100 for brainlies 50 points
Dmitrij [34]

Answer:

1. 650, 700 2. 840, 800 3. 370, 400 4. 80, 100 5. 620, 600 6. 250, 200 7. 970, 1,000 8. 330, 300 9. 450, 400 10. 210, 200 11. 100, 100 12. 710, 700

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • Mr.lobo is building a fence around his rectangular yard.It is 16 feet long and 14 feet wide.how many feet of fencing will he nee
    10·1 answer
  • A circle is described by the equation (x−1/2 )^2 +(y−3/2 )^2 =4/9 . What are the cordinates for the center of the circle and the
    5·1 answer
  • Five times the sum of a number and 3 is the same as 3 multiplied by 1 less than twice the number ​
    11·1 answer
  • Use the graph to solve the system of linear equations.<br> x+y=5<br> y – 2x = -4
    7·1 answer
  • 6th-grade math, fill out the table! :)
    11·1 answer
  • (a^4+4b^4)divided by (a^2-2ab+2b^2)
    15·1 answer
  • 2x - 9xy + 17y - xy. How many terms... Algebraic expression
    10·1 answer
  • I NEED THIS FOR A TEST PLZ HELP!!!
    9·2 answers
  • Please please help due in ten minutes!!!!!
    8·1 answer
  • Melissa ran "m" meters per second, and jasmine ran "j" meters per second. They ran for "t" seconds. The expression t(m-j) descri
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!