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Leto [7]
3 years ago
15

Factor each expression 36abc +54ad

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

18a(2bc + 3d)

Step-by-step explanation:

36abc + 54ad

Step 1: Find the Highest Common Factor of each

36abc = 2×2×3×3×a×b×c = 18a × 2bc

54ad = 2×3×3×3×a×d = 18a × 3d

HCF = 2×3×3×a = 18a

Step 2: Factor out with HCF

18a(2bc + 3d)

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Step-by-step explanation:

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What is the area of this figure? Round to the tenth if necessary.
Julli [10]

Answer:

<h3>b) 850.1 centimeters.</h3>

Step-by-step explanation:

To find the area of this figure, we must first find the areas of the shapes that compose this figure.

This figure is made up of a rectangle and a semicircle.

Remember: To find the area of a semicircle, multiply the radius by itself twice, then multiply the product pi, lastly divide the product by 2.

a=\pi r^2/2

<u>3.14 will be used for pi!</u>

To find the area of a rectangle, multiply the length by the width. The product is the area of the rectangle.

a=lw

Now, let's solve.

The diameter of the semicircle is 32 centimeters.

To find the radius of a semicircle, divide the diameter by 2.

32/2=16

The radius of the semicircle is 16 centimeters.

Now that we have the radius, we can find the area of the semicircle.

\pi 16^2/2=401.92

The area of the semicircle is 401.92 centimeters.

Furthermore, we find the area of the rectangle.

14*32=448.

The area of the circle is 448 centimeters.

Next, we add the areas of both shapes to find the area of this figure.

401.92+448

=849.92

The final step is to round 849.92 to the nearest tenth.

Even though 849.92 to rounded to the nearest tenth is 849.9, there is no answer choice for this. The closest one to this answer is choice 'b.'

I, therefore, believe the area of this figure is 850.1 centimeters.

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2 years ago
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Step-by-step explanation:

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You will need the same dataset used for problem 3 in homework 1 (the dataset obtained from the yahoo website with the company yo
stepladder [879]

Answer:

a) The probability of sampling at random a fish that is smaller in size than the value you would obtain by subtracting half the standard deviation from the average is 0.3085.

b) The probability of sampling at random a fish that is greater in size than the value you would obtain by adding half the standard deviation from the average is 0.3085.

c) The probability of sampling at random a fish that has a size between the two values is 0.383.

d) The 25th and 75 percentiles of fish size for the population using the normal distribution table is 5.69 and 5.87 respectively.

e) The probability that the average calculated will be less than the value is 0.3707.

Step-by-step explanation:

For the given data set mean (\mu) = 5.75913

Standard deviation (\sigma) = 0.172229

Variance (\sigma2) = 0.0296

Here we get is

a)

P(x < \mu - \sigma/2) = p(x < 5.673) \\\\          = 0.3085

b)

P(x < \mu + \sigma/2) = p(x < 5.845) \\\\= 0.3085

c)

P(\mu - \sigma/2 < x < \mu + \sigma/2) = p(5.673 < x < 5.845) \\\\= 0.383

d)

25th percentile:-

= 25*[(n+1)/100]th term \\\\= 5.69

75the percentile:-

= 75*[(n+1)/100]th term\\\\ = 5.87

e)  

p(x < \mu - \sigma/3) = p(x < 5.7017) \\\\= 0.3707

7 0
3 years ago
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