I assume
has counterclockwise orientation when viewed from above.
By Stokes' theorem,

so we first compute the curl:


Then parameterize
by

where the
-component is obtained from

with
and
.
Take the normal vector to
to be

Then the line integral is equal in value to the surface integral,



Answer:
The statement that is true is;
The vertices of the image are closer to the origin than those of the pre-image
Step-by-step explanation:
The dilation rule is 0.75(x,y)= (0.75x, 0.75y)
K (-4,4)----------( 0.75*-4,0.75*4)-------K' (-3,3)
L (2,4)-----------(0.75*2,0.75*4)---------L' (1.5,3)
M (-2,2)----------(0.75*-2,0.75*2)--------M' (-1.5,1.5)
The area of the base would be found using the area of a triangle formula which is 1/2 x base x height.
The base and height are the two sides perpendicular to each other, which are both 5 inches.
The area of the base = 1/2 x 5 x 5 = 12.5 square inches.
The volume of the triangular prism is the area of the base times the height, which is 4 inches.
Volume of the triangular prism is 12.5 x 4 = 50 cubic inches.
Volume of the triangular prism is 1/3 x area of base x height, which is 7:
Volume of the triangular prism = 1/3 x 12.5 x 7 = 29.17 cubic inches.
Total volume = 29.17 + 50 = 79.17 cubic inches.
Do a mental sum for 6 x 200 (1200) then subtract 6<span>x 2 (12) to give you 1188.</span>
To start off devide both sides by M i.e
K/M=LMN/M
-> K/M=LN
Then devide by K to remove it on the left , this will end you up with M=LN/K
So the answer is (c).
Hope this helps :).