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Archy [21]
3 years ago
5

Do I have this one correct

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0

Answer:

Option B is correct

Step-by-step explanation:

Given is a cos funciton.

Period = 3

Max = 20 and minimum =0

Hence centre line is y = 1/2 (max+min)

i.e. y =10 is the central line

Let the funciton be of the form

y = a cos (bx+C)+d

We got d = 10...i

Period =3

Hence b = \frac{2\pi}{3} ... ii

Amplitude = a = distance of max from central line = 20-10 =10...iii

Since reflection over x axis, sign of a =negative

a=-10

Since no horizontal shift, c=0 ... iv

Put to gether the function is

y=-10cos\frac{2\pi x}{3} +10

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Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
2 years ago
ASAP!!! help its emergent​
Bezzdna [24]

Answer:

Step-by-step explanation:

F(x)=(5 t^2+t  )x to x+3

=5((x+3)^2-x^2)+(x+3-x)

=5(x^2+6x+9-x^2)+3

=5 (6x+9)+3

=30x+48

F'(x)=30

3 0
3 years ago
What is the value of the expression x-3y when x = 6 and y = 12
elena55 [62]

Answer:

-30

Step-by-step explanation:

  1. Plug in the values of x and y: 6 - 3(12)
  2. 3(12) = 3 × 12 = 36
  3. Plug 36 in: 6 - 36
  4. 6 - 36 = -30

I hope this helps!

7 0
3 years ago
5 years ago, my grandfather was five times as old as I was. Three years from now, my grandfather will be three times as old as I
balu736 [363]
<h3>Answer:</h3>

13 years old

<h3>Explanation:</h3>

Let g and m represent grandfather's age now and my age now. The relation 5 years ago was ...

... g -5 = 5(m -5)

The relation in 3 years will be ...

... g +3 = 3(m +3)

Subtracting the first equation from the second, we get ...

... 8 = -2m +34

... 2m = 26 . . . . . add 2m-8

... m = 13

My age now is 13.

4 0
3 years ago
Read 2 more answers
If two are supplementary and one of the angles measure 62 what is the measure of the other angle
Juli2301 [7.4K]
Supplementary angles add to equal 180 degrees. If two angles are supplements of each other and one of the angles measures 62 degrees, you can set its sum with the unknown angle, x, equal to 180 and solve for the unknown angle x.

Equation:
180 = x + 62

Subtract 62 from both sides:
118 = x

Answer:
The measure of the other angle is 118°.
8 0
3 years ago
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