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galben [10]
3 years ago
5

What is x squared minus 64 equal to?

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0
X^2 - 64 = (x + 8)(x - 8)

hope it helps
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Math/Physics Problem <br> (I'd be glad if you solved one of them).
Whitepunk [10]

Answer:

19.2

76.8

Step-by-step explanation:

density × volume = mass

mass = 62.4 × (pi × (40/2)² × h)

mass = 78,374.4h

WD = m×9.8×h = 9.8mh

WD = 768,069.12h²

At h = 5

WD = 768,069.12×5²

= 19,201,728 ft-lb

= 19.2 million ft-lb

At h = 10

WD = 76,806,9.12 × 10²

WD = 76,806,912 ft-lb

= 76.8 million ft-lb

4 0
3 years ago
On the school picnic, 4 and 3/4 dozen hamburger rolls 5 and
guajiro [1.7K]
9 3/4dozens were used
5 0
3 years ago
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What is the value of x ??
ruslelena [56]

Answer:

A

Step-by-step explanation:

The Tangent-Secant Exterior Angle Measure Theorem states that if a tangent and a secant or two tangents/secants intersect outside of a circle, then the measure of the angle formed by them is half of the difference of the measures of its intercepted arcs. Basically, what that means here is that x equals half of the difference of 30\textdegree and the measure of the unlabeled arc.

First, we need to find the measure of the unlabeled arc, since we can't find x without it. We know that the measure of the full arc formed by the circle is 360\textdegree, so the measure of the unlabeled arc must be 360-30-100-100=130\textdegree by the Arc Addition Postulate.

Now, we can find x. Using all of the information known, we can solve for x like this:

\\x=\frac{1}{2} (130\textdegree-30\textdegree)\\=\frac{1}{2} (100\textdegree)\\=50\textdegree

Hope this helps!

5 0
2 years ago
If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No
Effectus [21]

If A and B are independent, then P(A\cap B)=P(A)P(B).

a.

P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)

P(A\cup B)=0.5+0.2-0.5\cdot0.2

\boxed{P(A\cup B)=0.6}

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)

P(A^c\cap B^c)=1-0.6

\boxed{P(A^c\cap B^c)=0.4}

c. DeMorgan's law can be used here too:

P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)

P(A^c\cup B^c)=1-0.5\cdot0.2

\boxed{P(A^c\cup B^c)=0.9}

4 0
2 years ago
What is -12x-5(-8)=40​
ololo11 [35]

Answer: 0

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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