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mixer [17]
3 years ago
15

Mathilde has 20 pints of green paint. She uses 2/5 of it to paint a landscape and 3 /10 of it while painting a clover. She decid

es that, for her next painting, she will need 14 pints of green paint. How much more paint will she need to buy?
Mathematics
1 answer:
atroni [7]3 years ago
5 0

Answer:

8

Step-by-step explanation:

Total pints of paint = 20

For landscape :

2/5 * 20 = 8 pints

For clover :

3/10 * 20 = 6 pints

Total used = (8 + 6) = 14

Pints left = 20 - 14 = 6 pints

14 required for next painting

14 - 6 = 8 pints

8 more pints needed

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Using English like form write an algorithm to find the area and perimeter of a rectangle
alexdok [17]

Answer:

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Step-by-step explanation:

ok so first you would find the area and perimeter and state how you got your answer

6 0
3 years ago
5. 18 m 11 m Not drawn to scale 29 m b. 445 m 7 m d. 203 m​
Luden [163]
Answer: D

Explanation: Apply the pythagorean theorem (a^2 + b^2 = c^2) to get 11^2 + b^2 = 18^2. From that you can solve for b and you get the square root of 203.

Hope this helped! :)
8 0
3 years ago
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Please help!!!! I'll give brainlist
Ymorist [56]

Answer:

Hello! answer: y = 122

Step-by-step explanation:

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3 years ago
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Tan(x+pi/2)= negative cot x
DIA [1.3K]
I'm only going to alter the left hand side. The right side will stay the same the entire time

I'll use the identity tan(x) = sin(x)/cos(x) and cot(x) = cos(x)/sin(x)
I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)

So with that in mind, this is how the steps would look:

tan(x+pi/2) = -cot x
sin(x+pi/2)/cos(x+pi/2) = -cot x
(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
(sin(x)*0+cos(x)*1)/(cos(x)*0-sin(x)*1) = -cot x
(0+cos(x))/(-sin(x)-0) = -cot x
(cos(x))/(-sin(x)) = -cot x
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Identity is confirmed

6 0
3 years ago
If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

By the quadratic formula,

x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2

Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}

Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

3 0
3 years ago
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