The two lines in this system of equations are parallel
Step-by-step explanation:
Let us revise the relation between 2 lines
- If the system of linear equations has one solution, then the two line are intersected
- If the system of linear equations has no solution, then the two line are parallel
- If the system of linear equations has many solutions, then the two line are coincide (over each other)
∵ The system of equation is
3x - 6y = -12 ⇒ (1)
x - 2y = 10 ⇒ (2)
To solve the system using the substitution method, find x in terms of y in equation (2)
∵ x - 2y = 10
- Add 2y to both sides
∴ x = 2y + 10 ⇒ (3)
Substitute x in equation (1) by equation (3)
∵ 3(2y + 10) - 6y = -12
- Simplify the left hand side
∴ 6y + 30 - 6y = -12
- Add like terms in the left hand side
∴ 30 = -12
∴ The left hand side ≠ the right hand side
∴ There is no solution for the system of equations
∴ The system of equations represents two parallel lines
The two lines in this system of equations are parallel
Learn more:
You can learn more about the equations of parallel lines in brainly.com/question/8628615
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Answer:
Slope intercept: y = -3/2x + 1
Point slope: y + 2 = -3/2 * (x - 2) [Forgot to add the work for this, I will add it if you need it, feel free to ask.]
Step-by-step explanation:
m = (change in y)/change in x)
But also
m = y_2 - y_1/x_2 - x_1
So lets substitute
m = 1 - (-2)/0 - (2)
Lets find the slope
m = 3/0 - (2)
m = 3/-2
m = -3/2 (Moved the negative)
Now we find the value of b using the equation of a line.
y = mx + b
y = (-3/2) * x + b
y = (-3/2) * (2) + b
-2 = (-3/2) * (2) + b
Now we find the value of b
Lets rewrite
-3/2 * 2 + b = -2
Cancel the CF of 2
-3 + b = -2
Move the terms without b to the right
b = -2 + 3
b = 1
Now we substitute our values of the slope and y-int into y = mx + b to find the equation.
y = -3/2x + 1
The answer tothis question is two
Answer:
<u>-</u><u>5</u><u>g</u><u>(</u><u>4</u><u>)</u><u> </u><u>-</u><u> </u><u>1</u><u> </u><u>is</u><u> </u><u>9</u>
Step-by-step explanation:
when x is 4:
therefore:
