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nalin [4]
3 years ago
15

What are the 3 steps to problem solving with efficiency?

Mathematics
1 answer:
Burka [1]3 years ago
7 0

Answer:

Step 1: Identify the Problem. ...

Step 2: Analyze the Problem. ...

Step 3: Describe the Problem. ...

Step 4: Look for Root Causes. ...

Step 5: Develop Alternate Solutions. ...

Step 6: Implement the Solution. ...

Step 7: Measure the Results.

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Evaluate v(x) = 12 - 2x - 5 when x = -2,0. and 5.
EleoNora [17]

Answer:

11,7,-3 respectively

Step-by-step explanation:

when x is -2 ,0 and 5 the result will be 11, 7 and -3 respectively

4 0
3 years ago
How do I get rid of log and ln?
insens350 [35]
Exponentiate the log or In because Exponentials are inverses of Logs and lns.
7 0
3 years ago
What is 1/3 plus 1/6?
Leya [2.2K]
The decimal is 0.0555555
4 0
3 years ago
Read 2 more answers
The total cost of a sweater and a pair of pants was $89.47. If the price of the sweater was $8.53 less than the pair of pants, w
Strike441 [17]

Answer:

Let S = price of sweater

Let P = price of pants

S + P = 89.47 because that was the total spent

S = P - 8.53   because the sweater is 8.53 less than pants

Substitute P-8.53 in place of S in the

1st equation and solve for P

P - 8.53 + P = 89.47

2P - 8.53 = 89.47     add 8.53 to both sides

2P = 89.47 + 8.53

2P = 98.00  divide both sides by 2

P = 98.00/2

P = $49.00

S = P - 8.53

S = 49.00-8.53

S = $40.47

A sweater costs $40.47 and the pants cost $49.00

5 0
3 years ago
There is a spinner with 15 equal areas, numbered 1 through 15. If the spinner is spun one time, what is the probability that the
NeX [460]

The probability that the result that is gotten will be a multiple of 3 and 2 will be 2/15.

<h3>How to calculate the probability</h3>

From the information, the spinner has 15 equal areas, numbered 1 through 15.

The multiple of 3 and a multiple of 2 among the numbers will be 6 and 15. Therefore, the probability will be two out of fifteen. This will be 2/15.

Learn more about multiples on:

brainly.com/question/1067440

8 0
3 years ago
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