Negative 4 decreased by the product of two and a number squared

The sign on a clearance rack tells customers the price is 1/2 the lowest marked price. If an item is marked $9.98, how much will

Artyom0805 [142]

Answer:

4.99

Step-by-step explanation:

9.98 divide by 2

3 0

3 years ago

Evaluate Each Expression. (Show Your Work.)

Anna11 [10]

Answer:

1. 8^2

2. 3^4

3. 5^3

Step-by-step explanation:

1)8×8 = 64

2)3×3×3×3=81

3)5×5×5=125

3 0

3 years ago

A city of 6,688 has an area of 16 square miles. What is the population density of the city?

Ahat [919]

To find population density, it is population / area.

The population is 6688, divided by the area of 16.

6688/16 = 418

So the population density is 418 people per sq mile.

7 0

3 years ago

A rectangular prism has a length of 11 mm and with a 5 mm. Its height is double its weight. What is the surface area of the pris

kkurt [141]

Answer:

C. 430

Step-by-step explanation:

length: 11

weight: 5

height (double of weight): 10

2 * (5 * 11 + 10 * 11 + 10 * 5)= 430

4 0

2 years ago

Crash Hospital Costs. A study was conducts to estimate hospital costs for accident victims who wore seat belts. Twenty randomly

kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =9004$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=20-1=19$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that $t_{\alpha/2}=2.86$

Now we have everything in order to replace into formula (1):

$9004-2.86\frac{5629}{\sqrt{20}}=5004.168$

$9004+2.86\frac{5629}{\sqrt{20}}=12603.832$

So on this case the 99% confidence interval would be given by (5004.168;12603.832)

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

7 0

2 years ago