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3 years ago

What is the third quartile, Q3, of the following distribution?

Mathematics

2 answers:

Mama L [17]3 years ago

7 0

Answer:

Step-by-step explanation:

GREYUIT [131]3 years ago

5 0

Answer:

The third quartile is:

$Q_3=29$

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile $Q_3$

For a set of n data organized in the form:

$x_1, x_2, x_3, ..., x_n$

The third quartile is $Q_3$ :

$Q_3=x_{\frac{3}{4}(n+1)}$

With n=20

$Q_3=x_{\frac{3}{4}(20+1)}$

$Q_3=x_{15.75}$

The third quartile is between $x_{15}=29$ and $x_{16}=29$

Then

$Q_3 =x_{15} + 0.75*(x_{16}- x_{15})$

$Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29$

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You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh

lorasvet [3.4K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

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3 years ago

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Murrr4er [49]

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3 years ago

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salantis [7]

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3 years ago

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- Write a recursive formula to represent the sequence below. (3,7, 11, 15, 19,23,27,31,35, ...)

NemiM [27]

The recursive formula to find nth term of sequence is:

$a_n = 4n - 1 \text{ where } n \geq 1$ and n = 1, 2, 3, ....

Solution:

Given a sequence is:

3, 7, 11, 15, 19, 23, 27, 31, 35

Let us find the difference between terms

7 - 3 = 4

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

23 - 19 = 4

27 - 23 = 4

31 - 27 = 4

35 - 31 = 4

Thus the difference between terms is constant

Thus the given sequence is arithmetic sequence

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

The nth term of arithmetic sequence is given by:

$a_n =a_1+(n-1)d$

$a_n$ = the nᵗʰ term in the sequence

$a_1$ = the first term in the sequence

d = the common difference between terms

Here in the given sequence

d = 4

$a_1=3$

Substitute in above formula,

$a_n = 3 + (n-1)(4)\\\\a_n = 3 + 4n - 4\\\\a_n = 4n - 1$

Thus the recursive formula to find nth term of sequence is:

$a_n = 4n - 1 \text{ where } n \geq 1$ and n = 1, 2, 3, ......

8 0

3 years ago

Carl is boarding a plane. He has 222 checked bags of equal weight and a backpack that weighs 4 Write an equation to determine th

dangina [55]

Answer: 2w + 4 = 35

Step-by-step explanation:

Carl's two checked bags and his one backpack together weigh 35kg.

Carl's two checked bags have equal weight so both their weight can be denoted as 2w.

Equation is;

2w + 4 = 35

If you were to solve;

2w + 4 = 35

2w = 35 - 4

w = 31/2

w = 15.5kg

4 0

2 years ago