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Over [174]
4 years ago
14

Question 1 (1 point)

Mathematics
2 answers:
musickatia [10]4 years ago
8 0

Answer:

c

Step-by-step explanation:

5 is added to -5 to make sum zero

ra1l [238]4 years ago
8 0
I think the answer is c it would make more sense
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(y^4 – y^3 + 2y^2 + y – 1) ÷ (y^3 + 1)<br> DO NOT INCLUDE PARENTHESES IN YOUR ANSWER
jarptica [38.1K]
Use long division.

                                     y - 1
         -------------------------------
y³+1  | y⁴  - y³  + 2y²  + y  - 1
          y⁴                    + y
         -------------------------------
               - y³  + 2y²         - 1
               - y³                    - 1
              ---------------------------
                         2y²

Answer:  y - 1 + 2y2 ÷ y³+1

Note:  
The correct answer should be written with parenthesis, as y - 1 + y²/(y³+1) in order to avoid ambiguity. 
8 0
4 years ago
A right cylindrical vase holds 2.50 L of water. If the radius of the vase is 9.00 cm, what is the height of the vase, rounded to
AVprozaik [17]

Answer:

Step-by-step explanation:1

3 0
3 years ago
Read 2 more answers
(Brainliest Award) Peter and Paula are both members of a population, and a simple random sample is being conducted. If the chanc
ZanzabumX [31]
If the sample is truly random, every member of the population should have an equal chance to be selected. Because of this, Paula and Peter's probability of being chosen will be equal: 1/9800
8 0
3 years ago
On what intervals is the graph of f(x)=x^3-2x^2+5x+1 increasing?
amid [387]
f(x)=x^3-2x^2+5x+1\\ f'(x)=3x^2-4x+5\\&#10;3x^2-4x+5=0\\\Delta=(-4)^2-4\cdot3\cdot5=16-60=-44
\Delta0 \Rightarrow the graph of the parabola is above the x-axis, so the derivative is always positive and therefore the initial function is increasing in its whole domain.

f(x)=0.5x^2-6\\&#10;f'(x)=x
The function is decreasing when its first derivative is negative. The first derivative of this function is negative for x so for x\in(-\infty,0) the function is decreasing.

f(x)=\dfrac{x+1}{x-1}\qquad(x\not=1)\\&#10;f'(x)=\dfrac{x-1-(x+1)}{(x-1)^2}=-\dfrac{2}{(x-1)^2}
The function is increasing when its first derivative is positive. The first derivative of this function is always negative therefore this function is never increasing.


3 0
4 years ago
6 x (+6) =<br> Need help please
Likurg_2 [28]

Answer: 36

Step-by-step explanation:

multiply

7 0
4 years ago
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