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3 years ago

What are the real zeros of f(x) = x^3 +2x^2-5x-6

1 answer:

8 0

First of all Horner
First we try with -3
1. 2. -5. -6.
-3. 3. 6
1. -1. -2. 0
To verify: -3^3+2*-3^2+15-6=0

Now we have this equation
(X+3)*(x^2 - x -2)=0

I dont know If you know sum and product but that is the easiest way so sum= 1 product = 2 so 2 and -1 are the answers.
You can do this too by this way : b^2-4ac= D
X= (-b(+or-)d^1/2)/2a

So all the zeros
2, -1 and -3
If you want more explanation, send me a comment x

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The difference of two numbers is 16 and the sum of their squares is 130. What are the numbers.

Korvikt [17]

x - y = 16
x^2 + x^2 = 130

----------------
x^2 - y^2 = 256
+(x^2 + y^2 = 130)
2x^2 = 386
x^2 = 193
x = <span>13.892 (3DP)
----
</span>x - y = 16
13.892 - y = 16
-y = 2.108
y = -2.108
The numbers are: 13.892 and -2.108

4 0

3 years ago

I need help with this plzzz

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3 0

3 years ago

Read 2 more answers

Write a linear function f with f(0)=7 and f(3)=1.

choli [55]

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a = ( 0 , 7 ) & b = ( 3 , 1 )

First need to find the slope using the following equation :

$slope = \frac{y(b) - y(a)}{x(b) - x(a)} \\$

$slope = \frac{1 - 7}{3 - 0} \\$

$slope = \frac{ - 6}{3} \\$

$slope = - 2$

_________________________________

We have following equation to find the point-slope form of the linear functions using the slope and one of the through points .

$y - y(0) = m \times ( \: x - x(0) \: )$

$x(0) = x - coordinate \: \: of \: \: through \: \: point \\$

$y(0) = y - coordinate \: \: of \: \: through \: \: point \\$

$m = slope$

I choose point (( a )) to put in the equation.

$y - 7 = - 2 \times (x - 0)$

$y - 7 = - 2x + 0$

$y - 7 = - 2x$

Add sides 7

$y - 7 + 7 = - 2x + 7$

$y = - 2x + 7$

This the slope-intercept form .

Done...

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7 0

2 years ago

Written as a simplified polynomial in standard form, what is the result when (x-8)^2

neonofarm [45]

Answer:

26x-67-x²

Step-by-step explanation:

We are given

$(10x - 3) - (x - 8) {}^{2}$

Expanding (x-8)²=x²-16x+64

10x-3-(x²-16x+64)

10x-3-x²+16x-64

26x-67-x²

3 0

2 years ago

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below

BARSIC [14]

Answer:

Due to the higher Z-score, Demetria should be offered the job.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Whichever applicant had grade with the highest z-score should be offered the job.

Demetria got a score of 85.1; this version has a mean of 61.1 and a standard deviation of 12.

For Demetria, we have $X = 85.1, \mu = 61.1, \sigma = 12$ . So