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3 years ago

What are the real zeros of f(x) = x^3 +2x^2-5x-6

1 answer:

8 0

First of all Horner
First we try with -3
1. 2. -5. -6.
-3. 3. 6
1. -1. -2. 0
To verify: -3^3+2*-3^2+15-6=0

Now we have this equation
(X+3)*(x^2 - x -2)=0

I dont know If you know sum and product but that is the easiest way so sum= 1 product = 2 so 2 and -1 are the answers.
You can do this too by this way : b^2-4ac= D
X= (-b(+or-)d^1/2)/2a

So all the zeros
2, -1 and -3
If you want more explanation, send me a comment x

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Arte-miy333 [17]

Answer:

solution set of f(x) = g(x) is x∈{0,1}

Step-by-step explanation:

For all exponential functions b^x,

b^0 is always 1, and b^1 is always b.

f(x) = -3/4 x + 2

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3 years ago

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3 years ago

Solve each system of equations by graphing Y=3x+4 and y=-x-4

In-s [12.5K]

Y = 3x + 4
y = -x - 4

3x + 4 = -x - 4
3x + x = -4 - 4
4x = -8
x = -8/4
x = -2

y = 3x + 4
y = 3(-2) + 4
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3 years ago

A $52 video game is advertised for 20% off.If sales tax is 6% how much will the video game cost

Usimov [2.4K]

Answer:

S44.10

Step-by-step explanation:

20% of 52 is 41.6

6% of 41.6 is 2.49600 US$ which rounds to 2.50

2.50+41.6=44.1

$44.10

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3 years ago

A loaded 8-sided die is loaded so that the number 4 occurs 3/10 of the time while the other numbers occur with equal frequency.

Law Incorporation [45]

Answer:

4.4

Step-by-step explanation:

The sum of the probabilities of all possible outcomes is 1.

As the die is loaded so that the number 4 occurs 3/10 of the time, and the other numbers occur with equal frequency, then the probability of numbers 1, 2, 3, 5, 6, 7 and 8 being rolled is 1/10.

Create a probability distribution table for X, where X is the score on the loaded 8-sided die:

$\begin{array}{ | c | c | c | c | c | c | c | c | c |}\cline{1-9}x & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\\cline{1-9} & & & & & & & &\\ \text{P}(X=x) & \dfrac{1}{10} & \dfrac{1}{10} & \dfrac{1}{10} & \dfrac{3}{10} & \dfrac{1}{10} & \dfrac{1}{10} & \dfrac{1}{10} & \dfrac{1}{10}\\& & & & & & & &\\\cline{1-9}\end{array}$

Add a product row and a totals column:

$\begin{array}{ | c | c | c | c | c | c | c | c | c | c |}\cline{1-10}x & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 &\text{Total} \\ \cline{1-10} &&&&&&&&& \\ \text{P}(X=x) & \frac{1}{10} & \frac{1}{10} & \frac{1}{10} & \frac{3}{10} & \frac{1}{10} & \frac{1}{10} & \frac{1}{10} & \frac{1}{10} & 1\\ &&&&&&&&&\\ \cline{1-10} &&&&&&&&&\\\text{Product} & \frac{1}{10} & \frac{2}{10} & \frac{3}{10} & \frac{12}{10} & \frac{5}{10} & \frac{6}{10} & \frac{7}{10} & \frac{8}{10} & \frac{44}{10} \\ &&&&&&&&&\\\cline{1-10}\end{array}$

(The Product is row is the product of the score on the die and its probability).

The expected value (EV) is the sum of the product of each outcome and its probability.

Therefore, the expected value (EV) of this die is 44/10 = 4.4

6 0

2 years ago