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RideAnS [48]
3 years ago
13

What are the real zeros of f(x) = x^3 +2x^2-5x-6

Mathematics
1 answer:
netineya [11]3 years ago
8 0

First of all Horner
First we try with -3
1. 2. -5. -6.
-3. 3. 6
1. -1. -2. 0
To verify: -3^3+2*-3^2+15-6=0

Now we have this equation
(X+3)*(x^2 - x -2)=0

I dont know If you know sum and product but that is the easiest way so sum= 1 product = 2 so 2 and -1 are the answers.
You can do this too by this way : b^2-4ac= D
X= (-b(+or-)d^1/2)/2a

So all the zeros
2, -1 and -3
If you want more explanation, send me a comment x
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C'D' = 4

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CD = 4 so C'D' = 4

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3 years ago
A car travels at a constant speed of 45 km per hour for 5 min each wheel has a radius of 25 centimeters calculate the number of
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Answer:

477.47 revolutions

Step-by-step explanation:

From the information given:

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Given that the radius of each wheel = 25 centimeter

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= 50π cm

The distance traveled in 5 minutes is as follows:

Given that:

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6 0
2 years ago
.....................................
Mandarinka [93]

\frac{5}{a + 3} = \frac{3}{a - 2}

5(a - 2) = 3(a + 3)

5a - 10 = 3a + 9

5a - 3a = 9 + 10

2a = 19

a = \frac{19}{2} = 9 \frac{1}{2}

Answer = D.) a = 9 \frac{1}{2}

\textbf{Spymore}​

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add the 3 distances

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