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Furkat [3]
3 years ago
9

How many apples can be purchased for $10

Mathematics
1 answer:
masha68 [24]3 years ago
5 0

Answer:

Divide ten by the price of the apples.

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3/5 and 2/5<br> what is the common denomenator?
amid [387]

Answer:

5 is their common denominator

Step-by-step explanation:

A common denominator is when both denominators are the same.

5 0
3 years ago
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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
How do you write 281% as a decimal
VMariaS [17]
I think it would be 28100% i might be wrong
5 0
3 years ago
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The ratio of blue to yellow is 4:5 and there are 15 yellow how many blue is there?
KATRIN_1 [288]

Answer: 12 blue marbles

Step-by-step explanation: Set up a proportion.

4/5 = x/15

Solve for x, the number of blue marbles. Cross multiply. You will get 60 = 5x

Divide by 5 on each side.

x = 12

There are 12 blue marbles.

7 0
3 years ago
Helpppppppp due tomarro need help ver easy
Ksju [112]

E. -16.8

F. 4.6

G. -28

H. 3.6

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