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3 years ago

Solve for F: C=5(F-32)/9

1 answer:

5 0

C = 5(F-32)/9 Multiply each side by 9
9C = 5(F-32) Distribute
9C = 5F - 160 Add 160 to each side
9C + 160 = 5F Divide each side by 5
9/5C + 32 = F

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D. $\frac{27\pi}{2}$ inches.

Step-by-step explanation:

We have been given that the circle with center O has a minor arc BSA with a length of $3\pi^{2}$ inches. The central angle is 40°.

To find the circumference of circle we will use formula:

$\frac{\text{Central angle}}{2\pi}=\frac{\text{Arc length}}{2\pi r}$ , where $2\pi$ = measure of 360 degrees in radians and $2\pi r$ = circumference of circle.

Let us convert measure of central angle into radians.

$40^{o}=\frac{40*\pi}{180} =\frac{2\pi}{9}$

Upon substituting our given value in the formula we will get,

$\frac{\frac{2\pi}{9}}{2\pi}=\frac{\frac{3\pi}{2}}{2\pi r}$

$\frac{2\pi}{18\pi}=\frac{3\pi}{4\pi r}$

$\frac{1}{9}=\frac{3}{4r}$

Cross multiplying we will get,

$4r=27$

$r=\frac{27}{4}$

Hence, the radius of our circle is 27/4 inches.

Since the circumference of circle is $2\pi r$ . Upon substituting $r=\frac{27}{4}$ we will get,

$2\pi r=2\pi* \frac{27}{4}=\frac{27\pi}{2}$

Therefore, circumference of our given circle will be $\frac{27\pi}{2}$ inches and option D is the correct choice.

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2 years ago