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3 years ago

Factor by grouping:

1 answer:

3 0

The idea is to group up the terms into two groups, factor each group and then factor out the overall GCF

2x - 18 + xy - 9y
(2x - 18) + (xy - 9y)
2(x - 9) + (xy - 9y)
2(x - 9) + y(x - 9)
(2 + y)(x - 9)
(x - 9)(2 + y)

Answer: Choice B

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(y+6)^2-(y-2)^2 I got 16y+26 but it is wrong?

Gemiola [76]

Answer:

16y + 32

Step-by-step explanation:

Expand each term.

(y+6)² - (y-2)²

= (y+6)(y+6) - (y-2)(y-2)

= y² + 12y + 36 - (y² - 4y + 4)

Subtract the second group by changing each term's signs

= y² + 12y + 36 - y² + 4y - 4

Collect like terms

= 16y + 32

5 0

3 years ago

Garrett and Carter went to the movies last weekend. Together they bought 2 drinks and 2 popcorns. They spent a total of $12.50.

-BARSIC- [3]

The cost of one drink is $2.50 and cost of one popcorn is $3.75

Explanation

Suppose, the cost of one drink is $x$ dollar and cost of one popcorn is $y$ dollar.

Given that, total cost for 2 drinks and 2 popcorns is $12.50 and total cost for 6 drinks and 5 popcorns is $33.75

So, the system of equations will be......

$2x+2y=12.50 ..................................... (1)\\ \\ 6x+5y= 33.75 ..................................... (2)$

Multiplying equation (1) by -3 , we will get.....

$-3(2x+2y)=-3(12.50)\\ \\ -6x-6y=-37.50 ..................................... (3)$

Now, adding equation (2) and equation (3) , we will get ............

$5y-6y=33.75-37.50\\ \\ -y=-3.75\\ \\ y=3.75$

Plugging this $y=3.75$ into equation (1) ......

$2x+2(3.75)=12.50\\ \\ 2x+7.50=12.50\\ \\ 2x=12.50-7.50=5\\ \\ x=\frac{5}{2}=2.50$

So, the cost of one drink is $2.50 and cost of one popcorn is $3.75

6 0

3 years ago

3+-1/1/3 the first half is 3+-1 the second half is 1/3

kolbaska11 [484]

$\bf \cfrac{3\pm1}{\frac{1}{3}}\implies 
\begin{cases}
\cfrac{3+1}{\frac{1}{3}}\\\\
\cfrac{3-1}{\frac{1}{3}}
\end{cases}\\\\
-------------------------------\\\\$

$\bf \cfrac{3+1}{\frac{1}{3}}\implies \cfrac{4}{\frac{1}{3}}\implies \cfrac{\frac{4}{1}}{\frac{1}{3}}\implies \cfrac{4}{1}\cdot \cfrac{3}{1}\implies \cfrac{4\cdot 3}{1\cdot 1}\implies \cfrac{12}{1}\implies \boxed{12}
\\\\\\
\cfrac{3-1}{\frac{1}{3}}\implies \cfrac{2}{\frac{1}{3}}\implies \cfrac{\frac{2}{1}}{\frac{1}{3}}\implies \cfrac{2}{1}\cdot \cfrac{3}{1}\implies \cfrac{2\cdot 3}{1\cdot 1}\implies \cfrac{6}{1}\implies \boxed{6}$

6 0

3 years ago

How do you do trigonometric Ratios

iren2701 [21]

To calculate the sine of an angle, simply divide the length of the opposite side, 479.16, by the length of the hypotenuse, 610. To get the cosine, divide the length of the adjacent side, 377.5, by the length of the hypotenuse, 610.

4 0

3 years ago

Someone please help me asap!

miskamm [114]

I think the correct answer is C. because each if forming a right triangle when you trace it.

If i'm correct brainliest please

3 0

3 years ago