Whats 6 time 2 ufduuuurturtuuthhytiu
2 answers:
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Answer:
<h3>b) 850.1 centimeters.</h3>Step-by-step explanation:
To find the area of this figure, we must first find the areas of the shapes that compose this figure.
This figure is made up of a rectangle and a semicircle.
Remember: To find the area of a semicircle, multiply the radius by itself twice, then multiply the product pi, lastly divide the product by 2.
<u>3.14 will be used for pi!</u>
To find the area of a rectangle, multiply the length by the width. The product is the area of the rectangle.
Now, let's solve.
The diameter of the semicircle is 32 centimeters.
To find the radius of a semicircle, divide the diameter by 2.
The radius of the semicircle is 16 centimeters.
Now that we have the radius, we can find the area of the semicircle.
The area of the semicircle is 401.92 centimeters.
Furthermore, we find the area of the rectangle.
The area of the circle is 448 centimeters.
Next, we add the areas of both shapes to find the area of this figure.
The final step is to round 849.92 to the nearest tenth.
Even though 849.92 to rounded to the nearest tenth is 849.9, there is no answer choice for this. The closest one to this answer is choice 'b.'
I, therefore, believe the area of this figure is 850.1 centimeters.
Answer:
The image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:
- D' (0, 1)
- L' (1/2, 5/2) or L'(0.5, 2.5)
- W' (5/2, 2) or W'(2.5, 2)
`The figure of the dilated image is attached below.
Step-by-step explanation:
Given the triangle ΔDLW withe the vertices
- D(0, 2)
- L(1, 5)
- W(5, 4)
As the scale factor 1/2 < 0, thus the image triangle will be smaller than the original triangle.
The rule of dilation is given by
Dilation: (x, y) → (1/2x, 1/2y), centered at (0, 0)
D(0, 2) → D' (1/2x, 1/2y) → D' (1/2(0), 1/2(2)) = D' (0, 1)
L(1, 5) → L'(1/2x, 1/2y) → L'(1/2(1), 1/2(5)) = L' (1/2, 5/2)
W(5, 4) → W'(1/2x, 1/2y) → W'(1/2(5), 1/2(4)) = W' (5/2, 2)
Therefore, the image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:
- D' (0, 1)
- L' (1/2, 5/2) or L'(0.5, 2.5)
- W' (5/2, 2) or W'(2.5, 2)
`The figure of the dilated image is attached below.
