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Alexxx [7]
3 years ago
10

Is N² + N always an even number? Explain

Mathematics
1 answer:
qaws [65]3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

Yes.

Let's first start with even numbers. (N - even number)

Any even number squared, is an even number. Then, we add that squared even number to another even number which would give us an even number.

Now, let's see odd numbers.

Any odd number squared would be an odd number. When you add "N", it would be adding an odd number to an odd number, which gives you an even number.

OR

We can start by factoring the expression:

N^2+N=N(N+1)

This is essentially multiplying two consecutive numbers, which in turn means that one number has to be even, and one has to be odd. An odd number multiplied by an even number will always be even.

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2 years ago
Please solve this problem because tomorrow is my exam.<br><br>​
jonny [76]

Step-by-step explanation:

a). A = {x  ∈ R  I  5x-8 < 7}

5x - 8 < 7 <=> 5x < 8+7  <=> 5x < 15  =>

x < 3  => A = (-∞ ; 3)

A ∩ N = {0 ; 1 ; 2}

A - N* = (-∞ ; 3) - {1 ; 2}

b).  A = { x ∈ R  I  7x+2 ≤ 9}

7x+2 ≤ 9 <=> 7x ≤ 7  => x ≤ 1 => x ∈ (-∞ ; 1]

A ∩ N = {0 ; 1}

A-N* = (-∞ ; 1)

c). A = { x ∈ R  I  I 2x-1 I < 5}

I 2x-1 I < 5  <=> -5 ≤ 2x-1 ≤ 5  <=>

-4 ≤ 2x ≤ 6  <=> -2 ≤ x ≤ 3  => x ∈ [-2 ; 3]

A ∩ N = {0 ; 1 ; 2 ; 3}

A - N* = [-2 ; 3) - {1 ; 2}

d). A = {x ∈ R I I 6-3x I ≤ 9}

I 6-3x I ≤ 9  <=> -9 ≤ 6-3x ≤ 9  <=>

-15 ≤ -3x ≤ 3 <=> -5 ≤ -x ≤ 3  =>

-3 ≤ x ≤ 5  => x ∈ [-3 ; 5]

A ∩ N = {0 ; 1 ; 2 ; 3 ; 4 ; 5}

A - N* = [-3 ; 5) - {1 ; 2 ; 3 ; 4}

4 0
2 years ago
An article reported that what airline passengers like to do most on long flights is rest or sleep; in a survey of 3697 passenger
slava [35]

Answer:

Step-by-step explanation:

Hello!

The study variable is:

X: number of passengers that rest or sleep during a flight.

The sample taken is n=9 passengers and the probability of success, that is finding a passenger that either rested or sept during the flight, is p=0.80.

I'll use the binomial tables to calculate each probability, these tables give the values of accumulated probability: P(X≤x)

a. P(6)= P(X=6)

To reach the value of selecting exactly 6 passengers you have to look for the probability accumulated until 6 and subtract the probability accumulated until the previous integer:

P(X=6)= P(X≤6)-P(X≤5)= 0.2618-0.0856= 0.1762

b. P(9)= P(X=9)

To know the probability of selecting exactly 9 passengers that either rested or slept you have to do the following:

P(X≤9) - P(X≤8)= 1 - 0.8657= 0.1343

c. P(X≥6)

To know what percentage of the probability distribution is above six, you have to subtract from the total probability -1- the cumulated probability until 6 but without including it:

P(X≥6)= 1 - P(X<6)= 1 - P(X≤5)= 1 - 0.0856= 0.9144

I hope it helps!

6 0
3 years ago
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