Is N² + N always an even number? Explain
1 answer:
Answer:
Yes
Step-by-step explanation:
Yes.
Let's first start with even numbers. (N - even number)
Any even number squared, is an even number. Then, we add that squared even number to another even number which would give us an even number.
Now, let's see odd numbers.
Any odd number squared would be an odd number. When you add "N", it would be adding an odd number to an odd number, which gives you an even number.
OR
We can start by factoring the expression:
This is essentially multiplying two consecutive numbers, which in turn means that one number has to be even, and one has to be odd. An odd number multiplied by an even number will always be even.
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Answer: Choice A) There must be a vertical asymptote at x = c
Explanation:
The first limit says that as x approaches c from the left side, the f(x) or y values approach negative infinity. So the graph goes down forever as x approaches this c value from the left side.
The limit means that as x approaches c from the right side, the y values head off to positive infinity.
Either of these facts are enough to conclude that we have a vertical asymptote at x = c. We can think of it like an electric fence in which we can get closer to, but not actually touch it.
Answer:
(a) <em> </em><em>n</em> : 20 50 100 500
P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886 0.4444 0.5954 0.9376
(b) The correct option is (b).
Step-by-step explanation:
Let the random variable <em>X</em> represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.
The mean amount of deductions is, <em>μ</em> = $16,642 and standard deviation is, <em>σ</em> = $2,400.
Assuming that the random variable <em>X </em>follows a normal distribution.
(a)
Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:
- For a sample size of <em>n</em> = 20
- For a sample size of <em>n</em> = 50
- For a sample size of <em>n</em> = 100
- For a sample size of <em>n</em> = 500
<em> n</em> : 20 50 100 500
P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886 0.4444 0.5954 0.9376
(b)
The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample () approaches the whole population mean (
).
Consider the probabilities computed in part (a).
As the sample size increases from 20 to 500 the probability that the sample mean is within $200 of the population mean gets closer to 1.
So, a larger sample increases the probability that the sample mean will be within a specified distance of the population mean.
Thus, the correct option is (b).
Given
To obtain the minimum value of y, we first take the derivative of y
The derivative of y is:
Equating
gives the minimum value we require.
Doing that, we have:
So that
Therefore, the minimum value is x = 3