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Bess [88]
3 years ago
7

What is the x-intercept of the line with this equation, -2x +1/2y=18 (_,0) ,, and what are the x and y intercepts for y=1/4x-2

Mathematics
1 answer:
OLEGan [10]3 years ago
4 0
It could be 1/2 if you divide by 2
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Is 9.058 greater than less than or equal to 9.24<br>​
Crank

Answer:

9.058 is less than 9.24

Step-by-step explanation:

there is 0 in the tenth digit and there is 2 in the tenths digit so therefor, 9.058 is less than 9.24

Hope this helps:)

3 0
3 years ago
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A linear equation with one solution in it is
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2x+7=3x+3 is a linear equation with on solution
8 0
3 years ago
Area= 18yd squared, length= 6yd<br> width=
GenaCL600 [577]

Answer:

The width is 3 yds

Step-by-step explanation:

Area = length * width

18 = 6*w

Divide each side by 6

18/6 = 6w/6

3=w

The width is 3 yds

7 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
I don’t understand how to find the dimension,<br> Need help :c
slava [35]

Width = W

Length = 2 times the width plus 3 feet = 2W + 3

Area of triangle A = L * W

A = W (2W + 3)

20 = 2W^2 + 3W

2W^2 + 3W - 20 = 0

(W + 4) (2W - 5) = 0

W + 4 = 0; W = - 4 (width cannot be negative, excluded)

2W - 5 = 0

2W = 5

W = 2.5

L = 2W + 3 = 2(2.5) + 3 = 8

Answer:

Width = 2.5 feet and Length = 8 feet

Hope it helps.

8 0
3 years ago
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