All categories

3 years ago

What is the equivalent to 16 3/4

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

5 0

Answer:

16 and 3/4 is 7/4

Step-by-step explanation:

You might be interested in

Find the midpoint of the line segment with the endpoints A and B.

zavuch27 [327]

Answer:

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )\\$

From the question we have

$m = ( \frac{2 + 10}{2} \: , \: \frac{6 + 8}{2} ) \\ = (\frac{12}{2} \: , \: \frac{14}{2} ) \: \: \: \: \: \: \:$

We have the final answer as

Hope this helps you

3 0

3 years ago

Identify each of the following as rational or irrational

Lera25 [3.4K]

√23-irrational
104.42-rational
√64-irrational
49.396-rational
10.97846727460-rational

8 0

2 years ago

The world's largest university (by enrollment) is University A, followed by University B. If the enrollment in University A i

Sav [38]

Let x be the number of people at University B

x + (x+3.5) = 9.5
2x +3.5 = 9.5
2x = 6
x = 3 million students at University B

x + 3.5 = 3 + 3.5 = 6.5 million students at University A

8 0

3 years ago

What is the total weight of 10 buses that each weigh 12 1/3 tons?

Lapatulllka [165]

Answer:

123 tons

Step-by-step explanation:

1) Convert 12 1/3 tons to a decimal - 12.3

2) multiply 12.3 by 10 - 123 tons

7 0

3 years ago

Read 2 more answers

Use the four-step definition of the derivative to find f'(x) if f(x) = −4x^3 −1.

guapka [62]

$\stackrel{de finition \textit{ of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{[-4(x+h)^3-1]~~ - ~~[-4x^3-1]}{h} \\\\\\ \cfrac{[-4(x^3+3x^2h+3xh^2+h^3)-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{[-4x^3-12x^2h-12xh^2-4h^3-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{-4x^3-12x^2h-12xh^2-4h^3-1+4x^3+1}{h}\implies \cfrac{-12x^2h-12xh^2-4h^3}{h}$

$\cfrac{h(-12x^2-12xh-4h^2)}{h}\implies -12x^2-12xh-4h^2 \\\\\\ \lim\limits_{h\to 0}~-12x^2-12xh-4h^2\implies \lim\limits_{h\to 0}~-12x^2-12x(0)-4(0)^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \lim\limits_{h\to 0}~-12x^2~\hfill$

7 0

2 years ago